Advertisements
Advertisements
प्रश्न
Express the following in terms of angles between 0° and 45°:
cos74° + sec67°
Advertisements
उत्तर
cos74° + sec67°
= cos(90 - 16)° + sec(90 - 23)°
= sin16° + cosec23°
संबंधित प्रश्न
If `cosθ=1/sqrt(2)`, where θ is an acute angle, then find the value of sinθ.
Evaluate.
sin(90° - A) cosA + cos(90° - A) sinA
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
Find the value of x, if sin 2x = 2 sin 45° cos 45°
Use tables to find sine of 62° 57'
If the angle θ = –45° , find the value of tan θ.
If \[\frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta}\] write the value of \[\frac{1 - \cos^2 \theta}{2 - \sin^2 \theta}\]
If θ is an acute angle such that sec2 θ = 3, then the value of \[\frac{\tan^2 \theta - {cosec}^2 \theta}{\tan^2 \theta + {cosec}^2 \theta}\]
The value of
Evaluate: `(cos55°)/(sin 35°) + (cot 35°)/(tan 55°)`
