Advertisements
Advertisements
प्रश्न
Express the following in terms of angles between 0° and 45°:
cos74° + sec67°
Advertisements
उत्तर
cos74° + sec67°
= cos(90 - 16)° + sec(90 - 23)°
= sin16° + cosec23°
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
If tan A = cot B, prove that A + B = 90°.
Use trigonometrical tables to find tangent of 17° 27'
Use tables to find the acute angle θ, if the value of tan θ is 0.4741
Evaluate:
cos 40° cosec 50° + sin 50° sec 40°
Evaluate:
sin 27° sin 63° – cos 63° cos 27°
If A and B are complementary angles, prove that:
cot B + cos B = sec A cos B (1 + sin B)
Find A, if 0° ≤ A ≤ 90° and sin 3A – 1 = 0
If angles A, B, C to a ∆ABC from an increasing AP, then sin B =
The value of cos 1° cos 2° cos 3° ..... cos 180° is
Evaluate: `(cot^2 41°)/(tan^2 49°) - 2 (sin^2 75°)/(cos^2 15°)`
