Advertisements
Advertisements
प्रश्न
Use trigonometrical tables to find tangent of 42° 18'
Advertisements
उत्तर
tan 42° 18' = 0.9099
APPEARS IN
संबंधित प्रश्न
`\text{Evaluate }\frac{\tan 65^\circ }{\cot 25^\circ}`
Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°
if `tan theta = 3/4`, find the value of `(1 - cos theta)/(1 +cos theta)`
If `cot theta = 1/sqrt3` find the value of `(1 - cos^2 theta)/(2 - sin^2 theta)`
Find the value of x, if cos x = cos 60° cos 30° – sin 60° sin 30°
Use tables to find the acute angle θ, if the value of tan θ is 0.2419
Evaluate:
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
Find the sine ratio of θ in standard position whose terminal arm passes through (3, 4)
If A + B = 90°, then \[\frac{\tan A \tan B + \tan A \cot B}{\sin A \sec B} - \frac{\sin^2 B}{\cos^2 A}\]
In ∆ABC, `sqrt(2)`AC = BC, sin A = 1, sin2A + sin2B + sin2C = 2, then ∠A = ?, ∠B = ?, ∠C = ?
