मराठी

Evaluate: tan (55° – A) – cot (35° + A)

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प्रश्न

Evaluate:

tan (55° – A) – cot (35° + A)

मूल्यांकन
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उत्तर

tan (55° – A) – cot (35° + A)

= tan [90° – (35° + A)] – cot (35° + A)

= cot (35° + A) – cot (35° + A)

= 0

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Complimentary Angles for Tangent ( Tan ) and Contangency ( Cot )
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पाठ 21: Trigonometrical Identities - Exercise 21 (C) [पृष्ठ ३२८]

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सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 21 Trigonometrical Identities
Exercise 21 (C) | Q 5. (iv) | पृष्ठ ३२८
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