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Evaluate: tan (55° – A) – cot (35° + A)

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Question

Evaluate:

tan (55° – A) – cot (35° + A)

Evaluate
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Solution

tan (55° – A) – cot (35° + A)

= tan [90° – (35° + A)] – cot (35° + A)

= cot (35° + A) – cot (35° + A)

= 0

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Complimentary Angles for Tangent ( Tan ) and Contangency ( Cot )
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Chapter 21: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals] - EXERCISE 21 (F) [Page 334]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 21 Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
EXERCISE 21 (F) | Q 7. (iv) | Page 334
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