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प्रश्न
Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.
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उत्तर
Oxidation state of Pt in [Pt(CN)4]2− hybridisation is required for the availability of one d-orbital. Hence, there should be no unpaired electrons in the [Pt(CN)4]2− ion.
Pt (Z = 78) ⇒ 5d8 6s2
Pt2+ ⇒ 5d8
Since Cl− is a weak ligand, pairing of 3d electrons should not occur, but in a square-planar complex (dsp2) hybridisation, pairing of electrons in the 2 half-filled 5d orbitals occurs.
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संबंधित प्रश्न
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\[\ce{[Co(NH3)6]^{3+}}\]
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(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
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