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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.

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प्रश्न

Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.

Explain on the basis of valence bond theory, the experimental finding that [Ni(CN)4]2− ion with a square planar structure is diamagnetic and the [Ni(Cl)4]2− ion with tetrahedral geometry is paramagnetic.

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उत्तर

Nickel in [Ni(CN)4]2− is in the +2 oxidation state, i.e., nickel is present as Ni2+ ion and dsp2 hybrid orbitals.

[Ni(CN)4]2− Ni(28): 4s2 3d8
Ni2+(28): 4s0 3d8

CN is a strong field ligand, so it causes the pairing of electrons.

The strong ligand CN facilitates electron pairing. The complex is diamagnetic because it contains no unpaired electrons.

In [NiCl4]2−, the formation of the above complex can be explained by hybridization. Ni in the above compound is in the +2 oxidation state, i.e., Ni2+.

As Cl is a weak ligand, pairing of electrons does not take place. sp3 hybridisation of orbitals takes place, giving rise to tetrahedral geometry. As there are two unpaired electrons in the complex, it is paramagnetic.

It is paramagnetic due to the presence of unpaired electrons.

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अध्याय 5: Coordinate Compounds - Intext Questions [पृष्ठ १३५]

APPEARS IN

एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 5 Coordinate Compounds
Intext Questions | Q 5.5 | पृष्ठ १३५
नूतन Chemistry [English] Class 12 ISC
अध्याय 5 Coordination Compounds
LONG ANSWER TYPE QUESTIONS | Q 11. | पृष्ठ ५४८

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\[\ce{[Mn(CN)6]^{3-}}\]

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