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Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory: [CoF6]3−

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प्रश्न

Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:

[CoF6]3−

विस्तार में उत्तर
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उत्तर

Co(27) = [Ar] 3d74s2

Co3+ = [Ar] 3d64s0

F being a weak field ligand cannot pair electrons.

The oxidation state of cobalt in the complex is +3. Its electronic configuration is [Ar] 3d6. F ion provides a weak ligand field and is unable to pair up the unpaired electrons of the 3d orbitals. 

Hence, six equivalent hybrid orbitals are obtained by mixing of one 4s, three 4p and two 4d orbitals. Six empty sp3d2 hybrid orbitals are filled up by six electron pairs provided by F ion. The highly paramagnetic nature of the complex further confirms the presence of four unpaired electrons.

As d-orbitals of the outermost shell participate in hybridisation, the complexes thus formed are called outer orbital complexes.

Hence, [CoF6]3− is a paramagnetic and octahedral complex.

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अध्याय 5: Coordinate Compounds - Exercises [पृष्ठ १३९]

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On the basis of valence bond theory explain the nature of bonding in [CoF6]3 ion.

 


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During chemistry class, a teacher wrote \[\ce{[Ni(CN)4]^2-}\] as a coordination complex ion on the board. The students were asked to find out the magnetic behaviour and shape of the complex. Pari, a student, wrote the answer paramagnetic and tetrahedral whereas another student Suhail wrote diamagnetic and square planer.

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