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प्रश्न
Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)
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उत्तर
Octahedral complex, `[Co(NH_3)_6]^(3+)`. In this complex ion, the oxidation state of cobalt is +3.
It has the electronic configuration as 3d6. This complex involves the d2sp3 hybridisation.

The six pairs of electrons, one from each NH3 molecule, occupy the six hybrid orbitals. It proves that complex has octahedral geometry. An absence of unpaired electron makes this complex diamagnetic in nature.
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संबंधित प्रश्न
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Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
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Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Mn(CN)6]^{3-}}\]
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(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
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\[\ce{[Co(NH3)6]^{3+}}\]
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(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
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Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[FeCl6]^{4-}}\]
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(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
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