हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory: [Co(C2O4)3]3−

Advertisements
Advertisements

प्रश्न

Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:

[Co(C2O4)3]3−

दीर्घउत्तर
Advertisements

उत्तर

Electronic configuration of Co (Z = 27) = [Ar] 3d74s2

Electronic configuration of Co3+ = [Ar] 3d64s0

\[\ce{C2O^{2-}_4}\] is a strong field ligand due to which electrons are paired.

As there are 6 electrons, the hybridisation has to be sp3d2, forming an octahedral, inner orbital complex as per valence bond theory. Hence, it is clear that [Co(C2O4)3]3− is a diamagnetic and octahedral complex.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Coordinate Compounds - Exercises [पृष्ठ १३९]

APPEARS IN

एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 5 Coordinate Compounds
Exercises | Q 5.15 (iii) | पृष्ठ १३९
नूतन Chemistry [English] Class 12 ISC
अध्याय 5 Coordination Compounds
'NCERT TEXT-BOOK' Exercises | Q 9.15 (iii) | पृष्ठ ५५९

संबंधित प्रश्न

On the basis of valence bond theory explain the nature of bonding in [CoF6]3 ion.

 


Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.


Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:

[Fe(CN)6]4−


[NiCl4]2- is paramagnetic while [Ni(CO)4] is  diamagnetic though both are tetrahedral. Why? (Atomic no. Ni = 28) 


Using valence bond theory, explain the following in relation to the complexes given below:

\[\ce{[Mn(CN)6]^{3-}}\]

(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.


Using valence bond theory, explain the following in relation to the complexes given below:

\[\ce{[Cr(H2O)6]^{3+}}\]

(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.


Which of the statement given below is incorrect about H2O2?


When the hybridization state of carbon changes from sp3 to sp2 and finally to sp, the angle between hybridized orbital will


As the s-character of hybridised orbital increases, the bond angle


Which of the following has square planar structures?


Using valence bond theory, predict the hybridization and magnetic character of the following:

[CoF6]3– [Atomic number of Co = 27]


According to the valence bond theory, the hybridization of central metal atom is dsp2 for which one of the following compounds?


Write the hybridisation and magnetic behaviour of [CoF6]3−.

[Given: Atomic number of Co = 27]


The geometry and magnetic behaviour of the complex [Ni(CO)4] are ______.


Which of the following are paramagnetic?

  1. [NiCl4]2−
  2. Ni(CO)4
  3. [Ni(CN)4]2−
  4. [Ni(H2O)6]2+
  5. Ni(PPh3)4

Choose the correct answer from the options given below:


Given below are two statements:

Statement I: Both [Co(NH3)6]3+ and [CoF6]3− complexes are octahedral but differ in their magnetic behavior.

Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3− is paramagnetic.

In the light of the above statements, Choose the correct answer form the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×