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[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why? - Chemistry

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प्रश्न

[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why?

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उत्तर

Formation of [Cr(NH3)6]3+: The oxidation state of chromium in [Cr(NH3)6]3+ ion is +3. The electronic configuration of chromium is [Ar] 3d54s1. The hybridisation is shown in the following diagram:

The Cr3+ ion provides six vacant orbitals to accommodate six electron pairs from six ammonia molecules. As a result, the complex [Cr(NH3)6]3+ has d2sp3 hybridisation and is octahedral. The presence of three unpaired electrons in the complex explains its paramagnetic property.

Formation of [Ni(CN)4]2−In [Ni(CN)4]2− the oxidation state of Ni is +2 and its electronic configuration is 3d. Hybridisation can be explained as follows:

Each hybridised orbital accepts a pair of electrons from the cyanide ion. The absence of unpaired electrons confirms the diamagnetic behaviour of [Ni(CN)4]2−.

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अध्याय 5: Coordinate Compounds - Exercises [पृष्ठ १३९]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 5 Coordinate Compounds
Exercises | Q 5.19 | पृष्ठ १३९

संबंधित प्रश्न

On the basis of valence bond theory explain the nature of bonding in [CoF6]3 ion.

 


Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:

[Co(C2O4)3]3−


Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:

[CoF6]3−


Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)


Write the hybridisation and number of unpaired electrons in the complex `[CoF_6]^(3-)`. (Atomic No. of Co = 27)


Using valence bond theory, explain the following in relation to the complexes given below:

\[\ce{[Cr(H2O)6]^{3+}}\]

(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.


Using valence bond theory, explain the following in relation to the complexes given below:

\[\ce{[FeCl6]^{4-}}\]

(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.


The type of hybridization involved in Octahedral complexes is ______.


Write the hybridization and shape of the following complexes:

[Ni(CN)4]2−


How many radial nodes for 3p orbital?


When the hybridization state of carbon changes from sp3 to sp2 and finally to sp, the angle between hybridized orbital will


As the s-character of hybridised orbital increases, the bond angle


Which of the following has square planar structures?


What is the no. of possible isomers for the octahedral complex [Co(NH3)2(C2O4)2]?


Using Valence bond theory, explain the following in relation to the paramagnetic complex [Mn(CN)6]3− 

  1. type of hybridization
  2. magnetic moment value
  3. type of complex – inner, outer orbital complex

Which of the following are paramagnetic?

  1. [NiCl4]2−
  2. Ni(CO)4
  3. [Ni(CN)4]2−
  4. [Ni(H2O)6]2+
  5. Ni(PPh3)4

Choose the correct answer from the options given below:


Given below are two statements:

Statement I: Both [Co(NH3)6]3+ and [CoF6]3− complexes are octahedral but differ in their magnetic behavior.

Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3− is paramagnetic.

In the light of the above statements, Choose the correct answer form the options given below:


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