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[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why? - Chemistry

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प्रश्न

[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why?

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उत्तर

Formation of [Cr(NH3)6]3+: The oxidation state of chromium in [Cr(NH3)6]3+ ion is +3. The electronic configuration of chromium is [Ar] 3d54s1. The hybridisation is shown in the following diagram:

The Cr3+ ion provides six vacant orbitals to accommodate six electron pairs from six ammonia molecules. As a result, the complex [Cr(NH3)6]3+ has d2sp3 hybridisation and is octahedral. The presence of three unpaired electrons in the complex explains its paramagnetic property.

Formation of [Ni(CN)4]2−In [Ni(CN)4]2− the oxidation state of Ni is +2 and its electronic configuration is 3d. Hybridisation can be explained as follows:

Each hybridised orbital accepts a pair of electrons from the cyanide ion. The absence of unpaired electrons confirms the diamagnetic behaviour of [Ni(CN)4]2−.

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अध्याय 5: Coordinate Compounds - Exercises [पृष्ठ १३९]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 5 Coordinate Compounds
Exercises | Q 5.19 | पृष्ठ १३९
नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 9 Coordination Compounds
'NCERT TEXT-BOOK' Exercises | Q 9.19 | पृष्ठ ५५९

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