Advertisements
Advertisements
प्रश्न
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
Advertisements
उत्तर
Electronic configuration of Co: [Ar]184s23d7
Oxidation state of [CoF6]3− will be x + 6(−1) = −3; x = +3.
Because of the existence of four unpaired electrons, the hybridisation of the Co atom in [CoF6]3− is sp3d2, and the magnetic behaviour is paramagnetic.
APPEARS IN
संबंधित प्रश्न
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[Fe(CN)6]4−
Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)
Write the hybridisation and number of unpaired electrons in the complex `[CoF_6]^(3-)`. (Atomic No. of Co = 27)
[NiCl4]2- is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why? (Atomic no. Ni = 28)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Co(NH3)6]^{3+}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
Write the hybridization and shape of the following complexes:
[Ni(CN)4]2−
In a coordination entity, the electronic configuration of the central metal ion is t2g3 eg1
Is the coordination compound a high spin or low spin complex?
Which of the statement given below is incorrect about H2O2?
Which of the following has square planar structures?
Valence bond theory is based on the assumption that the bonds formed between the metal ions and ligands are ______
