Advertisements
Advertisements
प्रश्न
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
Advertisements
उत्तर
Electronic configuration of Co: [Ar]184s23d7
Oxidation state of [CoF6]3− will be x + 6(−1) = −3; x = +3.
Because of the existence of four unpaired electrons, the hybridisation of the Co atom in [CoF6]3− is sp3d2, and the magnetic behaviour is paramagnetic.
APPEARS IN
संबंधित प्रश्न
On the basis of valence bond theory explain the nature of bonding in [CoF6]3 ion.
[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why?
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[FeF6]3−
Write the hybridisation and number of unpaired electrons in the complex `[CoF_6]^(3-)`. (Atomic No. of Co = 27)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Mn(CN)6]^{3-}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
What is the no. of possible isomers for the octahedral complex [Co(NH3)2(C2O4)2]?
Using Valence bond theory, explain the following in relation to the paramagnetic complex [Mn(CN)6]3−
- type of hybridization
- magnetic moment value
- type of complex – inner, outer orbital complex
According to the valence bond theory, the hybridization of central metal atom is dsp2 for which one of the following compounds?
[Ni(CO)4] has tetrahedral geometry while [Ni(CN)4]2− has square planar, yet both exhibit diamagnetism. Explain.
[Atomic number: Ni = 28]
During chemistry class, a teacher wrote \[\ce{[Ni(CN)4]^2-}\] as a coordination complex ion on the board. The students were asked to find out the magnetic behaviour and shape of the complex. Pari, a student, wrote the answer paramagnetic and tetrahedral whereas another student Suhail wrote diamagnetic and square planer.
Evaluate Pari’s and Suhail’s responses.
