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प्रश्न
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
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उत्तर
Electronic configuration of Co: [Ar]184s23d7
Oxidation state of [CoF6]3− will be x + 6(−1) = −3; x = +3.
Because of the existence of four unpaired electrons, the hybridisation of the Co atom in [CoF6]3− is sp3d2, and the magnetic behaviour is paramagnetic.
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संबंधित प्रश्न
On the basis of valence bond theory explain the nature of bonding in [CoF6]3 ion.
Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.
Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.
Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Co(NH3)6]^{3+}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
Write the hybridization and shape of the following complexes:
[Ni(CN)4]2−
If orbital quantum number (l) has values 0, 1, 2 and 3, deduce the corresponding value of principal quantum number, n.
According to the valence bond theory, the hybridization of central metal atom is dsp2 for which one of the following compounds?
Which of the following are paramagnetic?
- [NiCl4]2−
- Ni(CO)4
- [Ni(CN)4]2−
- [Ni(H2O)6]2+
- Ni(PPh3)4
Choose the correct answer from the options given below:
Given below are two statements:
Statement I: Both [Co(NH3)6]3+ and [CoF6]3− complexes are octahedral but differ in their magnetic behavior.
Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3− is paramagnetic.
In the light of the above statements, Choose the correct answer form the options given below:
