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प्रश्न
[Ni(CO)4] has tetrahedral geometry while [Ni(CN)4]2− has square planar, yet both exhibit diamagnetism. Explain.
[Atomic number: Ni = 28]
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उत्तर
In [Ni(CN)4]2−, nickel is in a +2 oxidation state and the ion has the electronic configuration 3d8. The hybridisation scheme is shown in the diagram.
Whereas in [Ni(CO)4], Ni is in a +2 oxidation state and shows sp2 hybridisation due to which its geometry is tetrahedral.
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संबंधित प्रश्न
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\[\ce{[FeCl6]^{4-}}\]
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