Advertisements
Advertisements
Question
[Ni(CO)4] has tetrahedral geometry while [Ni(CN)4]2− has square planar, yet both exhibit diamagnetism. Explain.
[Atomic number: Ni = 28]
Advertisements
Solution
In [Ni(CN)4]2−, nickel is in a +2 oxidation state and the ion has the electronic configuration 3d8. The hybridisation scheme is shown in the diagram.
Whereas in [Ni(CO)4], Ni is in a +2 oxidation state and shows sp2 hybridisation due to which its geometry is tetrahedral.
APPEARS IN
RELATED QUESTIONS
Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.
Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[Fe(CN)6]4−
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[CoF6]3−
Write the hybridisation and number of unpaired electrons in the complex `[CoF_6]^(3-)`. (Atomic No. of Co = 27)
[NiCl4]2- is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why? (Atomic no. Ni = 28)
The type of hybridization involved in Octahedral complexes is ______.
If orbital quantum number (l) has values 0, 1, 2 and 3, deduce the corresponding value of principal quantum number, n.
Which of the following methods is used for measuring bond length?
During chemistry class, a teacher wrote \[\ce{[Ni(CN)4]^2-}\] as a coordination complex ion on the board. The students were asked to find out the magnetic behaviour and shape of the complex. Pari, a student, wrote the answer paramagnetic and tetrahedral whereas another student Suhail wrote diamagnetic and square planer.
Evaluate Pari’s and Suhail’s responses.
