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Question
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[FeCl6]^{4-}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
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Solution
\[\ce{[FeCl6]^{4-}}\]:
Fe2+ = 3d6 
(i) Hybridisation – sp3d2
(ii) Outer orbital complex
(iii) Paramagnetic
(iv) Magnetic moment = `sqrt(4(4 + 2))` = 4.9 B.M
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