Advertisements
Advertisements
Question
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
Advertisements
Solution
Electronic configuration of Co: [Ar]184s23d7
Oxidation state of [CoF6]3− will be x + 6(−1) = −3; x = +3.
Because of the existence of four unpaired electrons, the hybridisation of the Co atom in [CoF6]3− is sp3d2, and the magnetic behaviour is paramagnetic.
APPEARS IN
RELATED QUESTIONS
On the basis of valence bond theory explain the nature of bonding in [CoF6]3 ion.
Write the hybridisation and number of unpaired electrons in the complex `[CoF_6]^(3-)`. (Atomic No. of Co = 27)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Co(NH3)6]^{3+}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
If orbital quantum number (l) has values 0, 1, 2 and 3, deduce the corresponding value of principal quantum number, n.
As the s-character of hybridised orbital increases, the bond angle
Valence bond theory is based on the assumption that the bonds formed between the metal ions and ligands are ______
Using Valence bond theory, explain the following in relation to the paramagnetic complex [Mn(CN)6]3−
- type of hybridization
- magnetic moment value
- type of complex – inner, outer orbital complex
The geometry and magnetic behaviour of the complex [Ni(CO)4] are ______.
Which of the following are paramagnetic?
- [NiCl4]2−
- Ni(CO)4
- [Ni(CN)4]2−
- [Ni(H2O)6]2+
- Ni(PPh3)4
Choose the correct answer from the options given below:
Given below are two statements:
Statement I: Both [Co(NH3)6]3+ and [CoF6]3− complexes are octahedral but differ in their magnetic behavior.
Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3− is paramagnetic.
In the light of the above statements, Choose the correct answer form the options given below:
