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प्रश्न
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[Fe(CN)6]4−
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उत्तर
The oxidation state of iron in this complex ion is +2.
Electronic configuration of Fe = [Ar] 3d64s2
Electronic configuration of Fe2+ = [Ar] 3d6
The iron (II) ion must provide six vacant orbitals to accommodate the six electron pairs from the six cyanide ions. This can be achieved by the hybridisation method, in which the d-subshell electrons pair, since CN– ions are strong-field ligands.
Hence, six electron pairs from six cyanide ions occupy six hybrid orbitals of the iron (II) ion. Thus, no unpaired electrons are in any orbital, so [Fe(CN)6]4− shows diamagnetism. Hence, [Fe(CN)6]4− is diamagnetic and octahedral.
संबंधित प्रश्न
[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why?
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[FeF6]3−
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[Co(C2O4)3]3−
Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)
Write the hybridisation and number of unpaired electrons in the complex `[CoF_6]^(3-)`. (Atomic No. of Co = 27)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Mn(CN)6]^{3-}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[FeCl6]^{4-}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
The type of hybridization involved in Octahedral complexes is ______.
Write the hybridization and shape of the following complexes:
[Ni(CN)4]2−
If orbital quantum number (l) has values 0, 1, 2 and 3, deduce the corresponding value of principal quantum number, n.
How many radial nodes for 3p orbital?
As the s-character of hybridised orbital increases, the bond angle
Which of the following has square planar structures?
What is the no. of possible isomers for the octahedral complex [Co(NH3)2(C2O4)2]?
Using valence bond theory, predict the hybridization and magnetic character of the following:
[CoF6]3– [Atomic number of Co = 27]
According to the valence bond theory, the hybridization of central metal atom is dsp2 for which one of the following compounds?
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
[Ni(CO)4] has tetrahedral geometry while [Ni(CN)4]2− has square planar, yet both exhibit diamagnetism. Explain.
[Atomic number: Ni = 28]
Given below are two statements:
Statement I: Both [Co(NH3)6]3+ and [CoF6]3− complexes are octahedral but differ in their magnetic behavior.
Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3− is paramagnetic.
In the light of the above statements, Choose the correct answer form the options given below:
