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Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory: [CoF6]3− - Chemistry

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प्रश्न

Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:

[CoF6]3−

सविस्तर उत्तर
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उत्तर

Co(27) = [Ar] 3d74s2

Co3+ = [Ar] 3d64s0

F being a weak field ligand cannot pair electrons.

The oxidation state of cobalt in the complex is +3. Its electronic configuration is [Ar] 3d6. F ion provides a weak ligand field and is unable to pair up the unpaired electrons of the 3d orbitals. 

Hence, six equivalent hybrid orbitals are obtained by mixing of one 4s, three 4p and two 4d orbitals. Six empty sp3d2 hybrid orbitals are filled up by six electron pairs provided by F ion. The highly paramagnetic nature of the complex further confirms the presence of four unpaired electrons.

As d-orbitals of the outermost shell participate in hybridisation, the complexes thus formed are called outer orbital complexes.

Hence, [CoF6]3− is a paramagnetic and octahedral complex.

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पाठ 5: Coordinate Compounds - Exercises [पृष्ठ १३९]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 5 Coordinate Compounds
Exercises | Q 5.15 (iv) | पृष्ठ १३९

संबंधित प्रश्‍न

Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.


[Cr(NH3)6]3+ is paramagnetic while [Ni(CN)4]2− is diamagnetic. Explain why?


Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:

[FeF6]3−


Write the hybridisation and number of unpaired electrons in the complex `[CoF_6]^(3-)`. (Atomic No. of Co = 27)


Using valence bond theory, explain the following in relation to the complexes given below:

\[\ce{[Cr(H2O)6]^{3+}}\]

(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.


Using valence bond theory, explain the following in relation to the complexes given below:

\[\ce{[FeCl6]^{4-}}\]

(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.


The type of hybridization involved in Octahedral complexes is ______.


Write the hybridization and shape of the following complexes:

[Ni(CN)4]2−


In a coordination entity, the electronic configuration of the central metal ion is t2g3 eg1

Is the coordination compound a high spin or low spin complex?


How many radial nodes for 3p orbital?


As the s-character of hybridised orbital increases, the bond angle


Which of the following methods is used for measuring bond length?


According to the valence bond theory, the hybridization of central metal atom is dsp2 for which one of the following compounds?


The magnetic moment of [NiCl4]2− is ______.

[Atomic number: Ni = 28]


[Ni(CO)4] has tetrahedral geometry while [Ni(CN)4]2− has square planar, yet both exhibit diamagnetism. Explain.
[Atomic number: Ni = 28]


During chemistry class, a teacher wrote \[\ce{[Ni(CN)4]^2-}\] as a coordination complex ion on the board. The students were asked to find out the magnetic behaviour and shape of the complex. Pari, a student, wrote the answer paramagnetic and tetrahedral whereas another student Suhail wrote diamagnetic and square planer.

Evaluate Pari’s and Suhail’s responses.


Which of the following are paramagnetic?

  1. [NiCl4]2−
  2. Ni(CO)4
  3. [Ni(CN)4]2−
  4. [Ni(H2O)6]2+
  5. Ni(PPh3)4

Choose the correct answer from the options given below:


Given below are two statements:

Statement I: Both [Co(NH3)6]3+ and [CoF6]3− complexes are octahedral but differ in their magnetic behavior.

Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3− is paramagnetic.

In the light of the above statements, Choose the correct answer form the options given below:


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