Advertisements
Advertisements
प्रश्न
The magnetic moment of [NiCl4]2− is ______.
[Atomic number: Ni = 28]
पर्याय
1.82 BM
2.82 BM
4.42 BM
5.46 BM
Advertisements
उत्तर
The magnetic moment of [NiCl4]2− is 2.82 BM.
Explanation:
Nickel is in the +2 oxidation state in the paramagnetic and tetrahedral complex [NiCl4]2−, and the ion has the electronic configuration 3d8. The figure depicts the hybridization scheme.
μB.M = `sqrt("n"("n" + 2))`
= `sqrt(2(2 + 2))`
= `sqrt8`
= 2.82 BM
APPEARS IN
संबंधित प्रश्न
Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.
Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[Co(C2O4)3]3−
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[CoF6]3−
Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Co(NH3)6]^{3+}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
Which of the statement given below is incorrect about H2O2?
Using Valence bond theory, explain the following in relation to the paramagnetic complex [Mn(CN)6]3−
- type of hybridization
- magnetic moment value
- type of complex – inner, outer orbital complex
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
[Ni(CO)4] has tetrahedral geometry while [Ni(CN)4]2− has square planar, yet both exhibit diamagnetism. Explain.
[Atomic number: Ni = 28]
