Advertisements
Advertisements
प्रश्न
Using Valence bond theory, explain the following in relation to the paramagnetic complex [Mn(CN)6]3−
- type of hybridization
- magnetic moment value
- type of complex – inner, outer orbital complex
Advertisements
उत्तर
[Mn(CN)6]3-
Mn = [Ar]3d54s2
Mn3+ = [Ar]3d4
Mn (ground state)

Mn in +3 state

Mn in [Mn(CN)6]3-

d2sp3 hybridisation
xx are electrons donated by ligand CN-
Type of hybridization – d2sp3
Magnetic moment value – `sqrt(n(n + 2)) = sqrt(2(2 + 2))` = 2.87 BM ......(n = no. of unpaired electrons)
Type of complex – inner orbital
APPEARS IN
संबंधित प्रश्न
[NiCl4]2− is paramagnetic, while [Ni(CO)4] is diamagnetic, though both are tetrahedral. Why? (Atomic number of Ni = 28)
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[Fe(CN)6]4−
Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Cr(H2O)6]^{3+}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
The type of hybridization involved in Octahedral complexes is ______.
As the s-character of hybridised orbital increases, the bond angle
In Fe(CO)5, the Fe – C bond possesses
According to the valence bond theory, the hybridization of central metal atom is dsp2 for which one of the following compounds?
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
Given below are two statements:
Statement I: Both [Co(NH3)6]3+ and [CoF6]3− complexes are octahedral but differ in their magnetic behavior.
Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3− is paramagnetic.
In the light of the above statements, Choose the correct answer form the options given below:
