Advertisements
Advertisements
प्रश्न
Using Valence bond theory, explain the following in relation to the paramagnetic complex [Mn(CN)6]3−
- type of hybridization
- magnetic moment value
- type of complex – inner, outer orbital complex
Advertisements
उत्तर
[Mn(CN)6]3-
Mn = [Ar]3d54s2
Mn3+ = [Ar]3d4
Mn (ground state)

Mn in +3 state

Mn in [Mn(CN)6]3-

d2sp3 hybridisation
xx are electrons donated by ligand CN-
Type of hybridization – d2sp3
Magnetic moment value – `sqrt(n(n + 2)) = sqrt(2(2 + 2))` = 2.87 BM ......(n = no. of unpaired electrons)
Type of complex – inner orbital
APPEARS IN
संबंधित प्रश्न
[NiCl4]2− is paramagnetic, while [Ni(CO)4] is diamagnetic, though both are tetrahedral. Why? (Atomic number of Ni = 28)
Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.
Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[FeF6]3−
Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:
[Co(C2O4)3]3−
Using valence bond theory, explain the following in relation to the complexes given below:
\[\ce{[Cr(H2O)6]^{3+}}\]
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
Which of the following has square planar structures?
Using valence bond theory, predict the hybridization and magnetic character of the following:
[CoF6]3– [Atomic number of Co = 27]
Write the hybridisation and magnetic behaviour of [CoF6]3−.
[Given: Atomic number of Co = 27]
Which of the following are paramagnetic?
- [NiCl4]2−
- Ni(CO)4
- [Ni(CN)4]2−
- [Ni(H2O)6]2+
- Ni(PPh3)4
Choose the correct answer from the options given below:
