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प्रश्न
Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.
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उत्तर
The 78Pt is located in group 10 of the periodic table, and its configuration is 5d96s1. Hence, the configuration of Pt2+ is d8.
The hybridisation of the square-planar structure is dsp2. Since the unpaired electrons in the 5d pair up to form a vacant d-orbital for dsp2 hybridisation, there are no unpaired electrons.
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संबंधित प्रश्न
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\[\ce{[Mn(CN)6]^{3-}}\]
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\[\ce{[Co(NH3)6]^{3+}}\]
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