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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.

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प्रश्न

Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.

लघु उत्तर
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उत्तर

Oxidation state of Pt in [Pt(CN)4]2− hybridisation is required for the availability of one d-orbital. Hence, there should be no unpaired electrons in the [Pt(CN)4]2− ion.

Pt (Z = 78) ⇒ 5d8 6s2

Pt2+ ⇒ 5d8

Since Cl is a weak ligand, pairing of 3d electrons should not occur, but in a square-planar complex (dsp2) hybridisation, pairing of electrons in the 2 half-filled 5d orbitals occurs.

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पाठ 5: Coordinate Compounds - Intext Questions [पृष्ठ १३५]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 5 Coordinate Compounds
Intext Questions | Q 5.9 | पृष्ठ १३५

संबंधित प्रश्‍न

On the basis of valence bond theory explain the nature of bonding in [CoF6]3 ion.

 


Explain on the basis of valence bond theory that [Ni(CN)4]2− ion with square planar structure is diamagnetic and the [NiCl4]2− ion with tetrahedral geometry is paramagnetic.


Discuss the nature of bonding in the following coordination entity on the basis of valence bond theory:

[Co(C2O4)3]3−


Explain the geometry of `[Co(NH_3)_6]^(3+)` on the basis of hybridisation. (Z of Co = 27)


Using valence bond theory, explain the following in relation to the complexes given below:

\[\ce{[Co(NH3)6]^{3+}}\]

(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.


Using valence bond theory, explain the following in relation to the complexes given below:

\[\ce{[FeCl6]^{4-}}\]

(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.


Write the hybridization and shape of the following complexes:

[Ni(CN)4]2−


In a coordination entity, the electronic configuration of the central metal ion is t2g3 eg1

Is the coordination compound a high spin or low spin complex?


As the s-character of hybridised orbital increases, the bond angle


Which of the following has square planar structures?


In Fe(CO)5, the Fe – C bond possesses


Using valence bond theory, predict the hybridization and magnetic character of the following:

[CoF6]3– [Atomic number of Co = 27]


Write the hybridisation and magnetic behaviour of [CoF6]3−.

[Given: Atomic number of Co = 27]


The magnetic moment of [NiCl4]2− is ______.

[Atomic number: Ni = 28]


[Ni(CO)4] has tetrahedral geometry while [Ni(CN)4]2− has square planar, yet both exhibit diamagnetism. Explain.
[Atomic number: Ni = 28]


The geometry and magnetic behaviour of the complex [Ni(CO)4] are ______.


Which of the following are paramagnetic?

  1. [NiCl4]2−
  2. Ni(CO)4
  3. [Ni(CN)4]2−
  4. [Ni(H2O)6]2+
  5. Ni(PPh3)4

Choose the correct answer from the options given below:


Given below are two statements:

Statement I: Both [Co(NH3)6]3+ and [CoF6]3− complexes are octahedral but differ in their magnetic behavior.

Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3− is paramagnetic.

In the light of the above statements, Choose the correct answer form the options given below:


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