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प्रश्न
Explain [Co(NH3)6]3+ is an inner orbital complex, whereas [Ni(NH3)6]2+ is an outer orbital complex.
[At. No.: Co = 27, Ni = 28]
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उत्तर
When a complex uses the inner (n − 1)d orbitals for hybridisation, forming d2sp3 hybrid orbitals, it is known as an inner orbital complex. The complex [Co(NH3)6]3+ uses inner (n − 1)d orbitals and is therefore classified as an inner orbital complex.
On the other hand, when a complex is formed using the outer ndndnd orbitals for hybridisation, resulting in 2sp3d2 hybrid orbitals, it is called an outer orbital complex. The complex [Ni(NH3)6]2+ uses the outer orbitals and is therefore an outer orbital complex.
[Co(NH3)6]3+ Co = 27 = 4s2 3d7
Ammonia, being a strong ligand, pairs.
[Ni(NH3)6]2+ Ni = 28 = 4s2 3d8
Although it is a strong ligand, if pairing of electrons occurs, only one d-orbital remains available, so the complex cannot undergo d2sp3 hybridisation.
संबंधित प्रश्न
For the complex [Fe(H2O)6]+3, write the hybridisation, magnetic character and spin of the complex. (At, number : Fe = 26)
For the complex [Fe(CN)6]3–, write the hybridization type, magnetic character and spin nature of the complex. (At. number : Fe = 26).
Write the hybridization and magnetic behaviour of the complex [Ni(CO)4].
(At.no. of Ni = 28)
Write the hybridization and shape of the following complexe : [CoF6]3–
(Atomic number : Co = 27, Ni = 28)
[Fe(H2O)6]3+ is strongly paramagnetic whereas [Fe(CN)6]3− is weakly paramagnetic. Explain.
Amongst the following ions, which one has the highest magnetic moment value?
Write the hybridisation and magnetic character of [Co(C2O4)3]3–.
(At. no. of Co = 27)
Why is [NiCl4]2− paramagnetic while [Ni(CN)4]2− is diamagnetic? (Atomic number of Ni = 28)
Write the hybridization type and magnetic behaviour of the complex [Ni(CN)4]2−. (Atomic number of Ni = 28)
Write the hybridization and magnetic character of the following complexes:
[Fe(H2O)6]2+
(Atomic no. of Fe = 26)
Write the hybridization and magnetic character of the following complexes:
[Fe(CO)5]
(Atomic no. of Fe = 26)
Which of the following options are correct for \[\ce{[Fe(CN)6]^{3-}}\] complex?
(i) d2sp3 hybridisation
(ii) sp3d2 hybridisation
(iii) paramagnetic
(iv) diamagnetic
Why do compounds having similar geometry have different magnetic moment?
Assertion: \[\ce{[Fe(CN)6]^{3-}}\] ion shows magnetic moment corresponding to two unpaired electrons.
Reason: Because it has d2sp3 type hybridisation.
The correct order of magnetic moment (spin only value in B.m.) is:
