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प्रश्न
Explain [Co(NH3)6]3+ is an inner orbital complex, whereas [Ni(NH3)6]2+ is an outer orbital complex.
[At. No.: Co = 27, Ni = 28]
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उत्तर
When a complex uses the inner (n − 1)d orbitals for hybridisation, forming d2sp3 hybrid orbitals, it is known as an inner orbital complex. The complex [Co(NH3)6]3+ uses inner (n − 1)d orbitals and is therefore classified as an inner orbital complex.
On the other hand, when a complex is formed using the outer ndndnd orbitals for hybridisation, resulting in 2sp3d2 hybrid orbitals, it is called an outer orbital complex. The complex [Ni(NH3)6]2+ uses the outer orbitals and is therefore an outer orbital complex.
[Co(NH3)6]3+ Co = 27 = 4s2 3d7
Ammonia, being a strong ligand, pairs.
[Ni(NH3)6]2+ Ni = 28 = 4s2 3d8
Although it is a strong ligand, if pairing of electrons occurs, only one d-orbital remains available, so the complex cannot undergo d2sp3 hybridisation.
संबंधित प्रश्न
For the complex [Fe(H2O)6]+3, write the hybridisation, magnetic character and spin of the complex. (At, number : Fe = 26)
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[Ti(H2O6]3+ T is paramagnetic is nature due to
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Explain [Fe(CN)6]3− is an inner orbital complex, whereas [FeF6]3− is an outer orbital complex.
[Atomic number: Fe = 26]
