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Question
Predict the number of unpaired electrons in the square planar [Pt(CN)4]2− ion.
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Solution
Oxidation state of Pt in [Pt(CN)4]2− hybridisation is required for the availability of one d-orbital. Hence, there should be no unpaired electrons in the [Pt(CN)4]2− ion.
Pt (Z = 78) ⇒ 5d8 6s2
Pt2+ ⇒ 5d8
Since Cl− is a weak ligand, pairing of 3d electrons should not occur, but in a square-planar complex (dsp2) hybridisation, pairing of electrons in the 2 half-filled 5d orbitals occurs.
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