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Question
[NiCl4]2- is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why? (Atomic no. Ni = 28)
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Solution
[NiCl4]2-
Ni is in + 2 oxidation state.
3d8 configuration 
Cl- is weak field ligand. So, pairing doesnot occur.
sp3 hybridised orbitals of 2 Ni2+ 
[ ] NiCl is paramagnetic as n = 2
4 [ ( ) ] Ni CO Ni is in ‘0’ oxidation state
In presence of ‘CO’ pairing of e– takes place ‘CO’ is strong field ligand. So, with ‘CO
[Ni(CO)4] → 
[Ni(CO)4] → 
So, [Ni(CO)4] is diamagnetic as n = 0.
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