An SN1 reaction occurs through the formation of a carbocation intermediate. Alkyl halide (I) is tertiary (3°), whereas (II) is secondary (2°). As a result, (I) forms a tertiary carbocation, while (II) forms a secondary carbocation. Since the rate of an SN1 reaction increases with carbocation stability, and a tertiary carbocation is more stable than a secondary carbocation, compound (I), i.e., 2-chloro-2-methylpropane, undergoes the SN1 reaction faster than compound (II), i.e., 3-chloropentane.
Advertisements
Advertisements
प्रश्न
In the following pair of halogen compounds, which compound undergoes a faster SN1 reaction?

In the following pair of halogen compounds, which compound undergoes SN1 reaction faster and why?

Advertisements
उत्तर १
The activity of halogen compounds in SN1 reaction depends on the stability of the carbocation formed due to ionization. The order of stability is tertiary > secondary > primary. Hence, 3° alkyl chloride is more active than 2° alkyl chloride. Hence,3° alkyl chloride is more active in the SN1 reaction.
The compound which react faster is:

The carbocation, which will be more stable and responsible for the faster reaction, is:

उत्तर २
Notes
Students should refer to the answer according to their questions.
APPEARS IN
संबंधित प्रश्न
Write the isomers of the compound having the formula C4H9Br.
Write the structure of the major organic product in the following reaction:
\[\ce{CH3CH2CH2OH + SOCl2 ->}\]
Arrange the compounds of the following set in order of reactivity towards SN2 displacement:
1-Bromobutane, 1-Bromo-2, 2-dimethylpropane, 1-Bromo-2-methylbutane, 1-Bromo-3-methylbutane
What happens when methyl chloride is treated with KCN?
SN1 reactions are accompanied by racemization in optically active alkyl halides.
Which of the following is a primary halide?
Which among MeX, RCH2X, R2CHX and R3CX is most reactive towards SN2 reaction?
Racemic compound has ____________.
Identify the end product (C) in the following sequence:
\[\ce{C2H5OH ->[SOCl2][Pyridine] A ->[KCN {(alc.)}] B ->[2H2O/H^+] C}\]
Which of the following undergoes nucleophilic substitution exclusively by SN1 mechanism?
Compound ‘A’ with molecular formula \[\ce{C4H9Br}\] is treated with aq. \[\ce{KOH}\] solution. The rate of this reaction depends upon the concentration of the compound ‘A’ only. When another optically active isomer ‘B’ of this compound was treated with aq. \[\ce{KOH}\] solution, the rate of reaction was found to be dependent on concentration of compound and \[\ce{KOH}\] both.
(i) Write down the structural formula of both compounds ‘A’ and ‘B’.
(ii) Out of these two compounds, which one will be converted to the product with inverted configuration.
How do polar solvents help in the first step in SN1 mechanism?
Which one is the correct order of nucleophilic strength (pKa) of following nucleophiles?
In which reaction mechanism carbocation is formed?
The major product formed in the following reaction is:

Among the following compounds I - IV, which one forms a yellow precipitate on reacting sequentially with (i) NaOH (ii) dil. HNO3 (iii) AgNO3?
![]() |
![]() |
![]() |
![]() |
| I | II | III | IV |
Complete the reaction with the main product formed:

Convert bromoethane to propanamine.
Give the mechanism of the following reaction:
\[\ce{CH3CH2OH ->[H2SO4][413 K] CH3CH2-O-CH2CH3 + H2O}\]




