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प्रश्न
Which would undergo SN2 reaction faster in the following pair and why ?
CH3 – CH2 – Br and CH3 – CH2 – I
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उत्तर
CH3 – CH2 – I would undergo an SN2 reaction faster than CH3 – CH2 – Br. Since iodine is a better leaving group because of its large size, it will be released at a faster rate in the presence of an incoming nucleophile as compared to bromine.
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संबंधित प्रश्न
Write the mechanism of the following reaction:
\[\ce{{n}BuBr + KCN ->[EtOH-H2O] {n}BuCN}\]
Arrange the compounds of the following set in order of reactivity towards SN2 displacement:
1-Bromobutane, 1-Bromo-2, 2-dimethylpropane, 1-Bromo-2-methylbutane, 1-Bromo-3-methylbutane
Which of the following is optically inactive?
Tertiary alkyl halides are practically inert to substitution by SN2 mechanism because of ____________.
Which of the following is an optically active compound?
Aryl halides are extremely less reactive towards nucleophilic substitution. Predict and explain the order of reactivity of the following compounds towards nucleophilic substitution:
| (I) |  |
| (II) |  |
| (III) |  |
Which one is the correct order of nucleophilic strength (pKa) of following nucleophiles?
CCl4 is insoluble in water because:-
Which of the following compounds will show retention in configuration on nucleophile substitution by OH− ion?
Which of the following reactions is an example of nucleophilic substitution reaction?
