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प्रश्न
Which would undergo SN2 reaction faster in the following pair and why ?
CH3 – CH2 – Br and CH3 – CH2 – I
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उत्तर
CH3 – CH2 – I would undergo an SN2 reaction faster than CH3 – CH2 – Br. Since iodine is a better leaving group because of its large size, it will be released at a faster rate in the presence of an incoming nucleophile as compared to bromine.
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संबंधित प्रश्न
Write the major products(s) in the following:
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CH3CH2CH2CH2Br or \[\begin{array}{cc}
\ce{CH3CH2CHCH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{Br}\
\end{array}\]
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\[\ce{CH3-CH2-Cl}\] or \[\ce{C6H5-CH2-Cl}\]
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