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Question
Which would undergo SN2 reaction faster in the following pair and why ?
CH3 – CH2 – Br and CH3 – CH2 – I
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Solution
CH3 – CH2 – I would undergo an SN2 reaction faster than CH3 – CH2 – Br. Since iodine is a better leaving group because of its large size, it will be released at a faster rate in the presence of an incoming nucleophile as compared to bromine.
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\ce{CH3-CH-CH2-CH3}\\
|\phantom{........}\\
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