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Karnataka Board PUCPUC Science 2nd PUC Class 12

Solution of a Differential Equation

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Estimated time: 8 minutes
CBSE: Class 12

Introduction

A differential equation involves derivatives of an unknown function, and its solution is usually a function rather than a single number.

This topic explains the meaning of a solution of a differential equation and distinguishes between a general solution and a particular solution.

Maharashtra State Board: Class 12

Definition: Solution of Differential Equation

Any relation between independent and dependent variables which does not involve derivatives, such that this relation and the derivatives obtained from it satisfy the given differential equation, is called a solution of the differential equation.

Maharashtra State Board: Class 12

Definition: General Solution

A solution of a differential equation in which the number of arbitrary constants equals the order of the differential equation is called the general solution of the differential equation.

Maharashtra State Board: Class 12

Definition: Particular Solution

A solution obtained from the general solution by giving particular values to the arbitrary constants is called a particular solution.

CBSE: Class 12

Example 1

Verification of a particular function

Verify that \[y = e^{-3x}\] is a solution of \[\frac{d^2y}{dx^2} + \frac{dy}{dx} - 6y = 0\].

Step 1: Differentiate once

\[\frac{dy}{dx} = -3e^{-3x}\]

Step 2: Differentiate again

\[\frac{d^2y}{dx^2} = 9e^{-3x}\]

Step 3: Substitute into the differential equation

\[\frac{d^2y}{dx^2} + \frac{dy}{dx} - 6y = 9e^{-3x} - 3e^{-3x} - 6e^{-3x} = 0\]

\[9e^{-3x} - 9e^{-3x}\] = 0

Conclusion: Hence, \[y = e^{-3x}\] is a solution of the given differential equation.

CBSE: Class 12

Example 2

Show that \[ y = a\sin(x+b), \qquad a, b \in R \] is a general solution of \[ \frac{d^{2}y}{dx^{2}} + y = 0. \] 

Also, obtain a particular solution when \[ a = 2, \qquad b = \frac{\pi}{4}. \]

Solution:

Given, \[ y = a\sin(x+b) \]

Differentiating, \[ \frac{dy}{dx} = a\cos(x+b) \]

Again differentiating, \[ \frac{d^{2}y}{dx^{2}} = -a\sin(x+b) \]

Therefore, \[ \frac{d^{2}y}{dx^{2}} + y = -a\sin(x+b) + a\sin(x+b) = 0 \]

Hence, \[ \boxed{\,y = a\sin(x+b)\,} \] is a general solution of \[ \frac{d^{2}y}{dx^{2}} + y = 0. \]

Now, putting

\[ a = 2, \qquad b = \frac{\pi}{4}, \] we get

\[ \boxed{\,y = 2\sin\left(x + \frac{\pi}{4}\right)\,} \]

which is a particular solution of the differential equation.

CBSE: Class 12

Key Points: General and Particular Solutions of a Differential Equation

  • A differential equation contains derivatives of an unknown function.
  • Its solution is generally a function, not a single number.

  • The graph of the solution function is called the solution curve or integral curve.

  • A general solution contains arbitrary constants.

  • A particular solution is obtained by assigning fixed values to those constants.

  • To verify a solution, substitute the function and its derivatives into the equation and check whether LHS = RHS.

Test Yourself

Video Tutorials

We have provided more than 1 series of video tutorials for some topics to help you get a better understanding of the topic.

Series 1


Series 2


Shaalaa.com | Finding General and Particular Solutions to Differential Equations

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Finding General and Particular Solutions to Differential Equations [00:13:30]
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