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R.D. Sharma solutions for Mathematics [English] Class 10 chapter 15 - Statistics [Latest edition]

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R.D. Sharma solutions for Mathematics [English] Class 10 chapter 15 - Statistics - Shaalaa.com
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Solutions for Chapter 15: Statistics

Below listed, you can find solutions for Chapter 15 of CBSE, Karnataka Board R.D. Sharma for Mathematics [English] Class 10.


EXERCISE 15.1EXERCISE 15.2EXERCISE 15.3EXERCISE 15.4EXERCISE 15.5EXERCISE 15.6VERY SHORT ANSWER TYPE QUESTIONS (VSAQS)FILL IN THE BLANK TYPE QUESTIONS (FBQS)
EXERCISE 15.1 [Pages 15.4 - 15.5]

R.D. Sharma solutions for Mathematics [English] Class 10 15 Statistics EXERCISE 15.1 [Pages 15.4 - 15.5]

BASIC

1.Page 15.4

Calculate the mean for the following distribution:-

x 5 6 7 8 9
f 4 8 14 11 3
2.Page 15.4

Find the missing value of p for the following distribution whose mean is 12.58

x 5 8 10 12 P 20 25
f 2 5 8 22 7 4 2
3.Page 15.5

The following table gives the number of boys of a particular age in a class of 40 students. Calculate the mean age of the students

Age (in years) 15 16 17 18 19 20
No. of students 3 8 10 10 5 4
4.Page 15.5

Five coins were simultaneously tossed 1000 times and at each toss the number of heads were observed. The number of tosses during which 0, 1, 2, 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss.

No. of heads per toss No. of tosses
0 38
1 144
2 342
3 287
4 164
5 25
Total 1000
5.Page 15.5

The arithmetic mean of the following data is 14. Find the value of k

x1 5 10 15 20 25
f1 7 k 8 4 5
6.Page 15.5

The arithmetic mean of the following data is 25, find the value of k.

x1 5 15 25 35 45
f1 3 k 3 6 2
7.Page 15.5

If the mean of the following data is 18.75. Find the value of p.

xi 10 15 P 25 30
fi 5 10 7 8 2

BASED ON LOTS

8.Page 15.5

Find the value of p, if the mean of the following distribution is 20.

x 15 17 19 20+P 23
f 2 3 4 5P 6
9.Page 15.5

Find the missing frequencies in the following frequency distribution if it is known that the mean of the distribution is 50.

x 10 30 50 70 90  
f 17 f1 32 f2 19 Total 120
EXERCISE 15.2 [Page 15.11]

R.D. Sharma solutions for Mathematics [English] Class 10 15 Statistics EXERCISE 15.2 [Page 15.11]

BASIC

1.Page 15.11

The number of telephone calls received at an exchange per interval for 250 successive one minute intervals are given in the following frequency table: 

No. of calls(x) 0 1 2 3 4 5 6
No. of intervals (f) 15 24 29 46 54 43 39

Compute the mean number of calls per interval.

2.Page 15.11

Five coins were simultaneously tossed 1000 times and at each toss the number of heads were observed. The number of tosses during which 0, 1, 2, 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss.

No. of heads per toss No. of tosses
0 38
1 144
2 342
3 287
4 164
5 25
Total 1000
3.Page 15.11

The marks obtained out of 50, by 102 students in a Physics test are given in the frequency table below:

Marks(x) 15 20 22 24 25 30 33 38 45
Frequency (f) 5 8 11 20 23 18 13 3 1

Find the average number of marks.

4.Page 15.11

The number of students absent in a class were recorded every day for 120 days and the information is given in the following frequency table:

No. of students absent (x) 0 1 2 3 4 5 6 7
No. of days (f) 1 4 10 50 34 15 4 2

Find the mean number of students absent per day.

EXERCISE 15.3 [Pages 15.18 - 15.20]

R.D. Sharma solutions for Mathematics [English] Class 10 15 Statistics EXERCISE 15.3 [Pages 15.18 - 15.20]

BASIC

1.Page 15.18

A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.

Number of plants 0 - 2 2 - 4 4 - 6 6 - 8 8 - 10 10 - 12 12 - 14
Number of houses 1 2 1 5 6 2 3

Which method did you use for finding the mean, and why?

2.Page 15.18

Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarized as follows. Fine the mean heartbeats per minute for these women, choosing a suitable method.

Number of heartbeats per minute 65 - 68 68 - 71 71 - 74 74 - 77 77 - 80 80 - 83 83 - 86
Number of women 2 4 3 8 7 4 2
3.Page 15.18

Find the mean of the following distribution:

Class: Frequency:
3 – 5 55
5 – 7 10
7 – 9 10
9 – 11 7
11 – 13 8
4.Page 15.18

The following distribution shows the daily pocket allowance given to the children of a multistorey building. The average pocket allowance is Rs 18.00. Find out the missing frequency.

Class interval 11 - 13 13 - 15 15 - 17 17 - 19 19 - 21 21 - 23 23 - 25
Frequency 7 6 9 13 - 5 4
5.Page 15.18

If the mean of the following distribution is 27, find the value of p.

Class 0 - 10 10 - 20 20 - 30 30 - 40 40 - 50
Frequency 8 p 12 13 10
6.Page 15.19

The table below shows the daily expenditure on food of 25 households in a locality.

Daily expenditure (in Rs) 100 − 150 150 − 200 200 − 250 250 − 300 300 − 350
Number of households 4 5 12 2 2

Find the mean daily expenditure on food by a suitable method.

7. (i)Page 15.19

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days: 0-6 6-12 12-18 18-24 24-30 30-36 36-42
Number of students: 10 11 7 4 4 3 1
7. (ii)Page 15.19

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days 0 - 6 6 - 10 10 -14 14 -20 20 -28 28 -38 38 -40
Number of students 11 10 7 4 4 3 1
8.Page 15.19

The following table gives the literacy rate (in percentage) of 35 cities. Find the mean literacy rate.

Literacy rate (in %) 45 − 55 55 − 65 65 − 75 75 − 85 85 − 95
Number of cities 3 10 11 8 3
9.Page 15.19

 The following is the cumulative frequency distribution ( of less than type ) of 1000 persons each of age 20 years and above . Determine the mean age .

Age below (in years): 30 40 50 60 70 80
Number of persons : 100 220 350 750 950 1000
10.Page 15.19

The marks obtained by 110 students in an examination are given below:

Marks: 30-35 35-40 40-45 45-50 50-55 55-60 60-65
Frequencу: 14 16 28 23 18 8 3

Find the mean marks of the students.

BASED ON LOTS

11.Page 15.19

Find the mean of the following data using assumed mean method:

Class 0 – 5 5 – 10 10 – 15 15 – 20 20 – 25
Frequency 8 7 10 13 12
12.Page 15.19

Find the mean of each of the following frequency distributions

Classes 25 - 29 30 - 34 35 - 39 40 - 44 45 - 49 50 - 54 55 - 59
Frequency 14 22 16 6 5 3 4
13.Page 15.19

The mean of the following frequency distribution is 62.8 and the sum of all the frequencies is 50. Compute the missing frequency f1 and f2.

Class 0 - 20 20 - 40 40 - 60 60 - 80 80 - 100 100 - 120
Frequency 5 f1 10 f2 7 8
14.Page 15.19

In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number of mangoes. The following was the distribution of mangoes according to the number of boxes.

Number of mangoe 50 − 52 53 − 55 56 − 58 59 − 61 62 − 64
Number of boxes 15 110 135 115 25

Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?

15.Page 15.19

To find out the concentration of SO2 in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below:

concentration of SO2 (in ppm) Frequency
0.00 − 0.04 4
0.04 − 0.08 9
0.08 − 0.12 9
0.12 − 0.16 2
0.16 − 0.20 4
0.20 − 0.24 2

Find the mean concentration of SO2 in the air.

16.Page 15.20

If the mean of the following frequency distribution is 18, find the missing frequency.

Class interval 11 – 13 13 – 15 15 – 17 17 – 19 19 – 21 21 – 23 23 – 25
Frequency 3 6 9 13 f 5 4
17.Page 15.20

The daily income of a sample of 50 employees are tabulated as follows:

Income (in Rs.): 1-1200 201 -400 401-600 601 - 800
No.of employees : 14 15 14 7

Find the mean daily income of employees.

18.Page 15.20

The mean of the following frequency distribution is 25. Find the value of f.

Class 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
Frequency 5 18 15 f 6
19.Page 15.20

The following table shows the age of patients admitted in a hospital during a particular week:

Age (in years): 5 - 15 15 - 25 25 - 35 35 - 45 45 - 55 55 - 65
Number of patients: 5 12 20 24 15 4

Find the mean age of patients.

20.Page 15.20

Find the mean of the following frequency distribution:

Classes: 25 - 30 30 - 35 35 - 40 40 - 45 45 - 50 50 - 55 55 - 60
Frequency: 14 22 16 6 5 3 4
21.Page 15.20

In a test, the marks obtained by 100 students (out of 50) are given below: 

Marks obtained: 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
Number of students: 12 23 34 25 6

Find the mean marks of the students. 

22.Page 15.20

The following distribution shows the weekly pocket allowance of 64 children of a locality.If the mean pocket allowance is ₹ 180, find the values of x and y.

Pocket
allowance (in ₹):
110-130 130-150 150-170 170-190 190-210 210-230 230-250
Number of
children:
7 6 9 13 x 5 y
EXERCISE 15.4 [Pages 15.28 - 15.31]

R.D. Sharma solutions for Mathematics [English] Class 10 15 Statistics EXERCISE 15.4 [Pages 15.28 - 15.31]

BASIC

1.Page 15.28

Following are the lives in hours of 15 pieces of the components of aircraft engine. Find the median:

715, 724, 725, 710, 729, 745, 694, 699, 696, 712, 734, 728, 716, 705, 719.

2.Page 15.29

The table below shows the salaries of 280 persons:

Salary (In thousand Rs) No. of Persons
5-10 49
10-15 133
15-20 63
20-25 15
25-30 6
30-35 7
35-40 4
40-45 2
45-50 1

Calculate the median salary of the data.

3.Page 15.29

Calculate the missing frequency from the following distribution, it being given that the median of the distribution is 24.

Age in years 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
No. of persons 5 25 ? 18 7
4.Page 15.29

Find the following table gives the distribution of the life time of 400 neon lamps:

Life time (in hours) Number of lamps
1500 – 2000 14
2000 – 2500 56
2500 – 3000 60
3000 – 3500 86
3500 – 4000 74
4000 – 4500 62
4500 – 5000 48

Find the median life time of a lamp.

5.Page 15.29

The distribution below gives the weights of 30 students of a class. Find the median weight of the students.

Weight (in kg) 40−45 45−50 50−55 55−60 60−65 65−70 70−75
Number of students 2 3 8 6 6 3 2
6.Page 15.29

A survey regarding the height (in cm) of 51 girls of class X of a school was conducted and the following data was obtained:

Height in cm Number of Girls
Less than 140 4
Less than 145 11
Less than 150 29
Less than 155 40
Less than 160 46
Less than 165 51

Find the median height.

7.Page 15.29

A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 years.

Age (in years) Number of policy holders
Below 20 2
20 - 25 4
25 - 30 18
30 - 35 21
35 - 40 33
40 - 45 11
45 - 50 3
50 - 55 6
55 - 60 2
8.Page 15.29

The lengths of 40 leaves of a plant are measured correct to the nearest millimeter, and the data obtained is represented in the following table:

Length (in mm) Number of leaves
118−126 3 
127–135 5
136−144 9
145–153 12
154–162 5
163–171 4
172–180 2

Find the mean length of the leaves.

9.Page 15.29

The frequency distribution given below shows the weight of 40 students of a class. Find the median weight of the students.

Weight (in kg): 40-45 45-50 50-55 55-60 60-65 65-70
No. of Students: 9 5 8 9 6 3

BASED ON LOTS

10.Page 15.29

An incomplete distribution is given below:

Variable: 10-20 20-30 30-40 40-50 50-60 60-70 70-80
Frequency: 12 30 - 65 - 25 18

You are given that the median value is 46 and the total number of items is 230.

(i) Using the median formula fill up missing frequencies.

(ii) Calculate the AM of the completed distribution.

11.Page 15.30

The median of the distribution given below is 14.4 . Find the values of x and y , if the total frequency is 20.

Class interval : 0-6 6-12 12-18 18-24  24-30
Frequency : 4 x  5 y 1
12.Page 15.30

The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.

Marks: 20 -30 30-40 40-50 50-60 60-70 70-80 80-90
Frequency: P 15 25 20 q 8 10
13.Page 15.30

Heights of 50 students of class X of a school are recorded and following data is obtained:

Height (in cm) 130 – 135 135 – 140 140 – 145 145 – 150 150 – 155 155 – 160
Number of students 4 11 12 7 10 6

Find the median height of the students.

14.Page 15.30

The monthly expenditure on milk in 200 families of a Housing Society is given below:

Monthly Expenditure
(in ₹)
1000 – 1500 1500 – 2000 2000 – 2500 2500 – 3000 3000 – 3500 3500 – 4000 4000 – 4500 4500 – 5000
Number of families 24 40 33 x 30 22 16 7

Find the value of x and also, find the median and mean expenditure on milk.

15.Page 15.30

A student noted the number of cars passing through a spot on a road for 100 periods each of 3 minutes and summarised it in the table given below. Find the mode of the data.

Number of cars 0 − 10 10 − 20 20 − 30 30 − 40 40 − 50 50 − 60 60 − 70 70 − 80
Frequency 7 14 13 12 20 11 15 8
16.Page 15.30

The lengths of 40 leaves of a plant are measured correct to the nearest millimeter, and the data obtained is represented in the following table:

Length (in mm) Number of leaves
118 − 126 3 
127 – 135 5
136 − 144 9
145 – 153 12
154 – 162 5
163 – 171 4
172 – 180 2

Find the median length of the leaves.

(Hint: The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 − 126.5, 126.5 − 135.5… 171.5 − 180.5)

17.Page 15.30

Find the mean and median for the following data:

Classes: 5-15 15-25 25-35 35-45 45-55 55-65 65-75
Frequencу: 2 3 5 7 4 2 2
18.Page 15.30

Medical check-up was carried out for 35 students of a class and their weights were recorded as follows:

Weight (in kg): 38-40 40-42 42-44 44-46 46-48 48-50 50-52
Number of students: 3 2 4 5 14 4 3

Find the difference between the mean weight and the median weight.

19.Page 15.30

During a medical checkup, height of 35 students of a class were recorded as follows:

Height (in cm): 90-100 100-110 110-120 120-130 130-140 140-150
Number of Students: 3 2 4 5 14 7

Find the difference between the mean height and median height.

20.Page 15.30

The following data shows the number of family members living in different bungalows of a locality:

Number of Members 0 − 2 2 − 4 4 − 6 6 − 8 8 − 10 Total
Number of Bungalows 10 p 60 q 5 120

If the median number of members is found to be 5, find the values of p and q.

21.Page 15.31

The population of lions was noted in different regions across the world in the following table:

Number of lions Number of regions
0 − 100 2
100 − 200 5
200 − 300 9
300 − 400 12
400 − 500 x
500 − 600 20
600 − 700 15
700 − 800 9
800 − 900 y
900 − 1000 2
  100

If the median of the given data is 525, find the values of x and y.

EXERCISE 15.5 [Pages 15.40 - 15.42]

R.D. Sharma solutions for Mathematics [English] Class 10 15 Statistics EXERCISE 15.5 [Pages 15.40 - 15.42]

BASIC

1. (i)Page 15.40

Find the mode of the following data:

3, 5, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4

1. (ii)Page 15.40

Find the mode of the following data:

3, 3, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4

1. (iii)Page 15.40

Find the mode of the following data:

15, 8, 26, 25, 24, 15, 18, 20, 24, 15, 19, 15

2.Page 15.40

The shirt sizes worn by a group of 200 persons, who bought the shirt from a store, are as follows:

Shirt size: 37 38 39 40 41 42 43 44
Number of persons: 15 25 39 41 36 17 15 12

Find the model shirt size worn by the group.

3. (i)Page 15.40

Find the mode of the following distribution.

Class-interval: 25 - 30 30 - 35 35 - 40 40 - 45 45 - 50 50 - 55
Frequency: 25 34 50 42 38 14

 

3. (ii)Page 15.40

Find the mode of the following frequency distribution.

Class 0-10 10-20 20-30 30-40 40-50 50-60 60-70
Frequency 8 10 10 16 12 6 7
4.Page 15.40

Compare the modal ages of two groups of students appearing for an entrance test:

Age (in years): 16-18 18-20 20-22 22-24 24-26
Group A: 50 78 46 28 23
Group B: 54 89 40 25 17
5.Page 15.40

The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:

Lifetimes (in hours) 0 − 20 20 − 40 40 − 60 60 − 80 80 − 100 100− 120
Frequency 10  35  52  61  38  29 

Determine the modal lifetimes of the components.

6.Page 15.40

The following table gives the daily income of 50 workers of a factory:

Daily income (in Rs) 100 - 120 120 - 140 140 - 160 160 - 180 180 - 200
Number of workers: 12 14 8 6 10

Find the mean, mode and median of the above data.

7.Page 15.40

The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.

Number of students
per teacher
Number of states/U.T.
15 − 20 3
20 − 25 8
25 − 30 9
30 − 35 10
35 − 40 3
40 − 45 0
45 − 50 0
50 − 55 2
8.Page 15.41

Find the mean, median and mode of the following data: 

Classes: 0 – 50 50 – 100 100 – 150 150 – 200 200 – 250 250 – 300 300 – 350
Frequency: 2 3 5 6 5 3 1
9.Page 15.41

A student noted the number of cars passing through a spot on a road for 100 periods each of 3 minutes and summarised it in the table given below. Find the mode of the data.

Number of cars 0 − 10 10 − 20 20 − 30 30 − 40 40 − 50 50 − 60 60 − 70 70 − 80
Frequency 7 14 13 12 20 11 15 8
10.Page 15.41

Find the mean, median and mode of the following data:

Classes: 0-20 20-40 40-60 40-60 80-100 100-120 120-140
Frequency: 6 8 10 12 6 5 3

 

11.Page 15.41

The frequency distribution for agriculture holdings in a village is given below:

Area of land (in hectares)  1 – 3  3 – 5   5 – 7 7 – 9 9 – 11 11 – 13
Number of families  20 45 80 55 40 12

Find the modal agriculture holdings of the village.

BASED ON LOTS

12.Page 15.41

The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.

Runs scored Number of batsmen
3000 − 4000 4
4000 − 5000 18
5000 − 6000 9
6000 − 7000 7
7000 − 8000 6
8000 − 9000 3
9000 − 10000 1
10000 − 11000 1

Find the mode of the data.

13.Page 15.41

 The monthly income of 100 families are given as below :

   Income in ( in  ₹)   Number of families
  0-5000   8
5000-10000  26
10000-15000 41
15000-20000 16
20000-25000  3
25000-30000 3
30000-35000   2
35000-40000      1

Calculate the modal income.

14. (i)Page 15.41

250 apples of a box were weighed and the distribution of masses of the apples is given in the following table:

Mass
(in grams)
80 – 100 100 – 120 120 – 140 140 – 160 160 – 180
Number of
apples
20 60 70 x 60

Find the value of x and the mean mass of the apples.

14. (ii)Page 15.41

250 apples of a box were weighed and the distribution of masses of the apples is given in the following table:

Mass
(in grams)
80 – 100 100 – 120 120 – 140 140 – 160 160 – 180
Number of
apples
20 60 70 x 60

Find the modal mass of the apples.

15.Page 15.41

The following table shows the ages of the patients admitted in a hospital during a year:

Age (in years) 5 − 15 15 − 25 25 − 35 35 − 45 45 − 55 55 − 65
Number of patients 6 11 21 23 14 5

Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.

16.Page 15.41

Find the mode of the following data:

Class: 1-3 3-5 5-7 7-9 9-11
Frequency: 7 8 2 2 1
17.Page 15.41

Find the mean and Mode of the following frequency distribution:

Class: 0-10 10-20 20-30 30-40 40-50 50-60 60-70
Frequencу: 8 7 15 20 12 8 10
18.Page 15.42

Find the Mean and Mode of the following data:

Class: 4-8 8-12 12-16 16-20 20-24 24-28 28-32 32-36
Frequency: 2 12 15 25 18 12 13 3
19.Page 15.42

The following table shows the number of patients of different age groups who were discharged from the hospital in a particular month:

Age (in years) Number of Patients Discharged
5 − 15 6
15 − 25 11
25 − 35 21
35 − 45 23
45 − 55 14
55 − 65 5
Total 80

Find the ‘mean’ and the ‘mode’ of the above data.

20.Page 15.42

The following table gives the daily income of 50 cab drivers of a particular city

Income (₹) 500 - 600 600 - 700 700 - 800 800 - 900 900 - 1000
No. of Drivers 12 14 8 6 10

Find the mean income and the modal income.

EXERCISE 15.6 [Page 15.53]

R.D. Sharma solutions for Mathematics [English] Class 10 15 Statistics EXERCISE 15.6 [Page 15.53]

BASIC

1.Page 15.53

Draw an ogive to represent the following frequency distribution:

Class-interval: 0 - 4 5 - 9 10 - 14 15 - 19 20 - 24
Frequency: 2 6 10 5 3
2.Page 15.53

The monthly profits (in Rs.) of 100 shops are distributed as follows:

Profits per shop: 0 - 50 50 - 100 100 - 150 150 - 200 200 - 250 250 - 300
No. of shops: 12 18 27 20 17 6

Draw the frequency polygon for it.

3.Page 15.53

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rs 100 − 120 120 − 140 140 − 160 160 − 180 180 − 200
Number of workers 12 14 8 6 10

Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

4.Page 15.53

The following table gives production yield per hectare of wheat of 100 farms of a village:

Production yield in kg per hectare: 50 - 55 55 - 60 60 - 65 65 - 70 70 - 75 75 - 80
Number of farms: 2 8 12 24 38 16

Draw ‘less than’ ogive and ‘more than’ ogive.

5.Page 15.53

During the medical check-up of 35 students of a class, their weights were recorded as follows:

Weight (in kg Number of students
Less than 38 0
Less than 40 3
Less than 42 5
Less than 44 9
Less than 46 14
Less than 48 28
Less than 50 32
Less than 52 35

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.

6.Page 15.53

The annual rainfall record of a city for 66 days is given in the following table :

Rainfall (in cm ):   0-10 10-20   20-30   30-40   40-50 50-60
Number of days : 22 10 8 15 5 6

Calculate the median rainfall using ogives of more than type and less than type.

7.Page 15.53

Change the following distribution to a 'more than type' distribution. Hence draw the 'more than type' ogive for this distribution.

Class interval: 20−30 30−40 40−50 50−60 60−70 70−80 80−90
Frequency: 10 8 12 24 6 25 15
8.Page 15.53

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in ₹) 200-220 220-240 240-260 260-280 280-300
Number of workers 12 14 8 6 10

Convert the distribution above to a 'less than type' cumulative frequency distribution and draw its ogive.

BASED ON LOTS

9.Page 15.53

The following table gives the height of trees:
 

Height No. of trees
Less than 7
Less than 14
Less than 21
Less than 28
Less than 35
Less than 42
Less than 49
Less than 56
26
57
92
134
216
287
341
360


Draw 'less than' ogive and 'more than' ogive.

 

10.Page 15.53

The annual profits earned by 30 shops of a shopping complex in a locality give rise to the following distribution:
 

Profit (in lakhs in Rs) Number of shops (frequency)
More than or equal to 5
More than or equal to 10
More than or equal to 15
More than or equal to 20
More than or equal to 25
More than or equal to 30
More than or equal to 35
30
28
16
14
10
7
3


Draw both ogives for the above data and hence obtain the median.

VERY SHORT ANSWER TYPE QUESTIONS (VSAQS) [Page 15.54]

R.D. Sharma solutions for Mathematics [English] Class 10 15 Statistics VERY SHORT ANSWER TYPE QUESTIONS (VSAQS) [Page 15.54]

BASIC

1.Page 15.54

Define mean.

2.Page 15.54

What is the algebraic sum of deviation of a frequency distribution about its mean?

3.Page 15.54

Which measure of central tendency is given by the x-coordinate of the point of intersection of the 'more than' ogive and 'less than' ogive?

4.Page 15.54

Write the empirical relation between mean, mode and median.

5.Page 15.54

Which measure of central tendency can be determine graphically?

6.Page 15.54

Find the mode of the following frequency distribution:

Classes: 0–20 20–40 40–60 60–80 80–100
Frequencies: 8 7 12 5 3
7.Page 15.54

If mode of the following frequency distribution is 55, then find the value of x.

Class 0 – 15 15 – 30 30 – 45 45 – 60 60 – 75 75 – 90
Frequency 10 7 x 15 10 12
8.Page 15.54

Write the modal class for the following frequency distribution:

Class-interval: 10−15 15−20 20−25 25−30 30−35 35−40
Frequency: 30 35 75 40 30 15

 

9.Page 15.54

Write the median class for the following frequency distribution:

Class-interval: 0−10 10−20 20−30 30−40 40−50 50−60 60−70 70−80
Frequency: 5 8 7 12 28 20 10 10
10.Page 15.54

In the graphical representation of a frequency distribution, if the distance between mode and mean is ktimes the distance between median and mean, then write the value of k.

11.Page 15.54

Find the class marks of classes 10−25 and 35−55.

12.Page 15.54

Write the median class of the following distribution:

Class-interval: 0−10 10−20 20−30 30−40 40−50 50−60 60−70
Frequency: 4 4 8 10 12 8 4
FILL IN THE BLANK TYPE QUESTIONS (FBQS) [Page 15.55]

R.D. Sharma solutions for Mathematics [English] Class 10 15 Statistics FILL IN THE BLANK TYPE QUESTIONS (FBQS) [Page 15.55]

BASIC

1.Page 15.55

If the mean of x, y, z is y, then mean of x and z is ______.

2.Page 15.55

The mode of the data 2, x, 3, 4, 5, 2, 4, 6, where x > 2, is ______.

3.Page 15.55

The mean of the first 673 natural numbers is ______.

4.Page 15.55

The mean of the observations 425, 430, 435, ..., 495 is ______.

5.Page 15.55

If the mean and median of a unimodal data are 34.5 and 32.5 respectively, then the mode of the data is ______.

6.Page 15.55

The mean of the first n odd natural numbers is ______.

7.Page 15.55

The mean of the observations 1, 3, 5, 7, 9, ..., 99 is ________.

8.Page 15.55

If the mean of the first n natural numbers is 20, then n = ______.

9.Page 15.55

If a mode exceeds a mean by 12, then the mode exceeds the median by ______.

BASED ON LOTS

10.Page 15.55

If the median of the observations x1, x2, x3, x4, x5, x6, x7, x8 is m, then the median of x3, x4, x5, x6 (where x1 < x2 < x3 < x4 < x5 < x6 < x7 < x8) is ______.

11.Page 15.55

If mode − median = 2, then median − mean = ______.

12.Page 15.55

If the average of a, b, c, d is the average of b and c, then the value of a − b − c + d is ______.

13.Page 15.55

Given that a, b, c, d are non-zero integers such that a < b < c < d. If the mean and median of a, b, c, d are equal to zero, then a = ______ and b = ______.

14.Page 15.55

If a < b < 2a and the mean and median of a, b and 2a are 15 and 12 respectively, then a = ______.

15.Page 15.55

If the mean of 26, 19, 15, 24 and x is x, then the median of the data is ______.

Solutions for 15: Statistics

EXERCISE 15.1EXERCISE 15.2EXERCISE 15.3EXERCISE 15.4EXERCISE 15.5EXERCISE 15.6VERY SHORT ANSWER TYPE QUESTIONS (VSAQS)FILL IN THE BLANK TYPE QUESTIONS (FBQS)
R.D. Sharma solutions for Mathematics [English] Class 10 chapter 15 - Statistics - Shaalaa.com

R.D. Sharma solutions for Mathematics [English] Class 10 chapter 15 - Statistics

Shaalaa.com has the CBSE, Karnataka Board Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.D. Sharma solutions for Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board 15 (Statistics) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in Mathematics [English] Class 10 chapter 15 Statistics are .

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