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Question
The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.
| Number of students per teacher |
Number of states/U.T. |
| 15 − 20 | 3 |
| 20 − 25 | 8 |
| 25 − 30 | 9 |
| 30 − 35 | 10 |
| 35 − 40 | 3 |
| 40 − 45 | 0 |
| 45 − 50 | 0 |
| 50 − 55 | 2 |
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Solution
It can be observed from the given data that the maximum class frequency is 10 belonging to class interval 30 − 35.
Therefore, modal class = 30 − 35
Class size (h) = 5
lower limit (l) of modal class is = 30
Frequency (f1) of modal class = 10
Frequency (f0) of the preceding modal class = 9
Frequency (f2) of the succeeding modal class = 3
`Mode = l+((f_1-f_0)/(2f_1-f_0-f_2) xxh)`
= `30+((10-9)/2(10)-9-3)xx(5)`
=`30+(1/(20-12))xx 5`
=` 30 + 5/8`
= 30.625
Mode = 30.6
It represents that most of the states and U.T. have a teacher-student ratio as 30.6.
To find the class marks, the following relation is used:
`"Class mark" = ("Upper class limit + Lower class limit")/2`
Taking 32.5 as the assumed mean (a), di, ui, and fiui are calculated as follows:
| Number of students per teacher |
Number of states/U.T. (fi) |
xi | di = xi − 32. | `u_i=d_i/5` | fiui |
| 15 − 20 | 3 | 17.5 | −15 | −3 | −9 |
| 20 − 25 | 8 | 22.5 | -10 | −2 | −16 |
| 25 − 30 | 9 | 27.5 | − 5 | −1 | −9 |
| 30 − 35 | 10 | 32.5 | 0 | 0 | 0 |
| 35 − 40 | 3 | 37.5 | 5 | 1 | 3 |
| 40 − 45 | 0 | 42.5 | 10 | 2 | 0 |
| 45 − 50 | 0 | 47.5 | 15 | 3 | 0 |
| 50 − 55 | 2 | 52.5 | 20 | 4 | 8 |
| Total | 35 | -23 |
Mean, `barx = a+((sumf_iu_i)/(sumf_i))xxh`
= `32.5 +((-23)/35)xx5`
= `32.5 - 23/7 `
= 32.5 - 3.28
= 29.22
Therefore, the mean of the data is 29.2.
It represents that, on average, the teacher-student ratio was 29.2
