Advertisements
Advertisements
Question
In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number of mangoes. The following was the distribution of mangoes according to the number of boxes.
| Number of mangoe | 50 − 52 | 53 − 55 | 56 − 58 | 59 − 61 | 62 − 64 |
| Number of boxes | 15 | 110 | 135 | 115 | 25 |
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
Sum
Advertisements
Solution
| Number of mangoes | Number of boxes |
| 50 − 52 | 15 |
| 53 − 55 | 110 |
| 56 − 58 | 135 |
| 59 − 61 | 115 |
| 62 − 64 | 25 |
Let the assumes mean a = 57
∴ di = xi - 57
Now, we have the following table:
| Number of mangoes | fi | xi | di = xi − 57 | fidi |
| 50 − 52 | 15 | 51 | − 6 | − 6 |
| 53 − 55 | 110 | 54 | − 3 | − 330 |
| 56 − 58 | 135 | 57 | 0 | 0 |
| 59 − 61 | 115 | 60 | 3 | 345 |
| 62 − 64 | 23 | 63 | 6 | 150 |
| Total | 400 | 75 |
It can be observed that
`sumf_i = 400`
`sumf_iu_i = 75`
∴ `barx = a + 1/N sumf_i d_i`
= `57 + 75/400`
= 57 + 0.1875
= 57.1875 ≈ 57.19
Thus, the average number of mangoes per box = 57.19, we choose the assumed mean method.
shaalaa.com
Is there an error in this question or solution?
