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During a medical checkup, height of 35 students of a class were recorded as follows: Height (in cm): 90-100 100-110 110-120 120-130 130-140 140-150 Number of Students: 3 2 4 5 14 7

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Question

During a medical checkup, height of 35 students of a class were recorded as follows:

Height (in cm): 90-100 100-110 110-120 120-130 130-140 140-150
Number of Students: 3 2 4 5 14 7

Find the difference between the mean height and median height.

Sum
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Solution

Using the class marks 95, 105, 115, 125, 135 and 145:

\[\sum f_i x_i=4485, \quad N=35\] 

\[\text{Mean height}=\frac{4485}{35}\approx 128.14\text{ cm}\] 

The cumulative frequency first exceeding `N/2 = 17.5` is 28, so the median class is 130–140. 

Here l = 130, h = 10, f = 14 and F = 14.

\[\text{Median height}=130+\frac{17.5-14}{14}\times 10=132.5\text{ cm}\] 

\[\text{Difference}=|132.5-128.14|\approx 4.36\text{ cm}\]

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Chapter 15: Statistics - EXERCISE 15.4 [Page 15.30]

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R.D. Sharma Mathematics [English] Class 10
Chapter 15 Statistics
EXERCISE 15.4 | Q 19. | Page 15.30
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