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Question
What happens when ethyl chloride is treated with aqueous KOH?
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Solution 1
\[\ce{CH3 - CH2 - Cl ->[KOH/H2O]\underset{(S_N2 reaction)}{CH3 - CH2 - OH}}\]
Solution 2
When ethyl chloride is treated with aqueous KOH, it undergoes dehydrohalogenation, which eliminates hydrogen and halogen atoms from nearby carbon atoms, resulting in the production of an alkene.
\[\ce{\underset{Ethyl chloride}{CH3 - CH2 - Cl} + KOH (aq) ->[hydrolysis][\Delta] \underset{Ethyl alcohol}{CH3 - CH2 - OH} + KCl}\]
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