Question

Write the isomers of the compound having the formula C₄H₉Br.

Answer 1

C₄H₉Br is a saturated compound because its parent hydrocarbon is C₄H₁₀.

Its isomers are as follows:

(i) \[\ce{\underset{1-Bromobutane}{CH3 - CH2 - CH2 - CH2 - Br}}\]

(ii) \[\begin{array}{cc}
\phantom{.........}\ce{Br}\\
\phantom{.......}|\\
\ce{\underset{2-Bromobutane}{CH3-CH2-CH-CH3}}
\end{array}\]

(iii) \[\begin{array}{cc}
\ce{CH3}\phantom{...}\\
|\phantom{......}\\
\ce{\underset{1-Bromo-2-Methylpropane}{CH3-CH-CH2Br}}
\end{array}\]

(iv) \[\begin{array}{cc}
\phantom{..}\ce{CH3}\\
|\phantom{..}\\
\ce{CH3 - C - Br}\phantom{.....}\\
|\phantom{..}\\
\phantom{..}\ce{\underset{2-Bromo-2-Methylpropane}{CH3}}
\end{array}\]