English
Karnataka Board PUCPUC Science 2nd PUC Class 12

A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon.

Advertisements
Advertisements

Question

A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon.

Classify
Long Answer
Advertisements

Solution

A hydrocarbon with the molecular formula C5H10 belongs to the group with a general molecular formula of CnH2n. Therefore, it may either be an alkene or a cycloalkane. Since hydrocarbons do not react with chlorine in the dark, they cannot be alkenes. Thus, it should be a cycloalkane. Further, the hydrocarbon gives a single monochloro compound, C5H9Cl, by reacting with chlorine in bright sunlight. Since a single monochloro compound is formed, the hydrocarbon must contain H-atoms that are all equivalent. Also, as all H-atoms of a cycloalkane are equivalent, the hydrocarbon must be a cycloalkane. Hence, the said compound is cyclopentane. The reactions involved are:

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Haloalkanes and Haloarenes - Exercises [Page 189]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 6 Haloalkanes and Haloarenes
Exercises | Q 6.5 | Page 189
Nootan Chemistry [English] Class 12 ISC
Chapter 6 Haloalkanes and Haloarenes
SHORT ANSWER TYPE QUESTIONS | Q 40. | Page 612

RELATED QUESTIONS

Why is sulphuric acid not used during the reaction of alcohols with KI?


Among the isomeric alkanes of molecular formula C5H12, identify the one that on photochemical chlorination yields a single monochloride.


Draw the structure of the major monohalo product in the following reaction:

\[\ce{CH3CH2Br + NaI ->}\]


Write the equation for the preparation of 1-iodobutane from 1-chlorobutane.


How will you bring about the following conversion?

Propene to 1-nitropropane


Write the structure of the major organic product in the following reaction:

\[\ce{CH3CH2CH2Cl + NaI ->[acetone][heat]}\]


Write the structure of the major organic product in the following reaction:

\[\ce{CH3CH2CH = CH2 + HBr->[peroxide]}\]


Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.


How the following conversion can be carried out?

Benzyl alcohol to 2-phenylethanoic acid


How the following conversion can be carried out?

But-1-ene to n-butyliodide


How the following conversion can be carried out?

tert-Butyl bromide to isobutyl bromide


Among the isomeric alkanes of molecular formula C5H12, identify the one that on photochemical chlorination yields three isomeric monochlorides.


3-Methyl-pent-2-ene of peroxide forms an addition product. The number of possible stereoisomers for the product is ______.


Alkyl halides are prepared from alcohols by treating with ______.


The reagent used in the conversion of 1-butanol to 1-bromobutane is ______.


Predict the major product ‘P’ in the following sequence of reactions:


How many products (including stereoisomers) are expected from the monochlorination of the following compound?

\[\begin{array}{cc}
\ce{H3C}\phantom{..................................}\\
\backslash\phantom{...........................}\\
\ce{CH - CH2 - CH3}\\
/\phantom{...........................}\\
\ce{H3C}\phantom{...................................}
\end{array}\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×