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प्रश्न
What happens when ethyl chloride is treated with aqueous KOH?
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उत्तर १
\[\ce{CH3 - CH2 - Cl ->[KOH/H2O]\underset{(S_N2 reaction)}{CH3 - CH2 - OH}}\]
उत्तर २
When ethyl chloride is treated with aqueous KOH, it undergoes dehydrohalogenation, which eliminates hydrogen and halogen atoms from nearby carbon atoms, resulting in the production of an alcohol.
\[\ce{\underset{Ethyl chloride}{CH3 - CH2 - Cl} + KOH_{(aq)} ->[hydrolysis][\Delta] \underset{Ethyl alcohol}{CH3 - CH2 - OH} + KCl}\]
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\ce{CH3CH2CHCH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{Br}\
\end{array}\]
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(i) \[\begin{array}{cc}
\phantom{}\ce{\underset{}{(CH3)2CH - CH2Br} ->[C2H5OH] \underset{}{(CH3)2CH - CH2OC2H5 + HBr}}\\
\end{array}\]
(ii) \[\begin{array}{cc}
\phantom{}\ce{\underset{}{(CH3)2CH - CH2Br} ->[C2H5O-] \underset{}{(CH3)2CH - CH2OC2H5 + Br-}}\\
\end{array}\]
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