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प्रश्न
How the following conversion can be carried out?
Ethyl chloride to propanoic acid.
Write the chemical equation to convert the following:
Ethyl chloride to propanoic acid.
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उत्तर
\[\ce{\underset{Ethyl chloride}{CH3CH2Cl} ->[KCN/EtOH-H2O][nucleophilic substitution] \underset{Propanenitrile}{CH3CH2CN} ->[H+/H2O][hydrolysis] \underset{Propanoic acid}{CH3CH2COOH}}\]
संबंधित प्रश्न
Which compound in the following pair will react faster in SN2 reaction with OH−?
CH3Br or CH3I
Write the mechanism of the following reaction:
\[\ce{{n}BuBr + KCN ->[EtOH-H2O] {n}BuCN}\]
Out of C6H5CH2Cl and C6H5CHClC6H5, which is more easily hydrolysed by aqueous KOH.
C–Cl bond length in chlorobenzene is shorter than C–Cl bond length in CH3–Cl.
What is the action of the following on ethyl bromide?
silver acetate
AgCN reacts with haloalkanes to form isocyanide. Haloalkanes react with KCN to form alkyl cyanides as the main product. Why?
In the reaction, \[\ce{R - X + NaOR' -> ROR’ + X}\] ( – ve ion). The main product formed is:
Among the following, the dissociation constant is highest for:
Which of the following undergoes nucleophilic substitution exclusively by SN1 mechanism?
Which of the compounds will react faster in SN1 reaction with the –OH ion?
\[\ce{CH3-CH2-Cl}\] or \[\ce{C6H5-CH2-Cl}\]
How do polar solvents help in the first step in SN1 mechanism?
Which one of the following compounds is more reactive towards SN1 reaction?
In SN1 reactions, the correct order of reactivity for the following compounds:
CH3Cl, CH3CH2Cl, (CH3)2CHCl and (CH3)3CCl is ______.
Complete the reaction with the main product formed:
Convert bromoethane to propanamine.
An organic compound A with the molecular formula (+) C4H9Br undergoes hydrolysis to form (+) C4H9OH. Give the structure of A and write the mechanism of the reaction.
Which alkyl halide from the following pair would you expect to react more rapidly by an SN2 mechanism? Explain your answer.
\[\begin{array}{cc}\ce{CH3CH2CHCH3}\\
\phantom{.....}|\\
\phantom{......}\ce{Br}\\
\end{array}\] or \[\begin{array}{cc}\phantom{.......}\ce{CH3}\\
\phantom{...}|\\
\ce{H3C - C - Br}\\
\phantom{...}|\\
\phantom{.......}\ce{CH3}\\
\end{array}\]
Assertion (A): 
undergoes SN2 reactions faster than 
.
Reason (R): Iodine is a better leaving group because of its large size.
In the light of the above statements, choose the correct answer from the options given below:
