Advertisements
Advertisements
Question
The velocity-time graph for part of a train journey is a horizontal straight line. What does this tell you about its acceleration ?
Advertisements
Solution
There is no acceleration as the object is moving with uniform velocity.
APPEARS IN
RELATED QUESTIONS
Show by using the graphical method that: `s=ut+1/2at^2` where the symbols have their usual meanings.
Derive the following equation of motion by the graphical method : v2 = u2 + 2as, where the symbols have their usual meanings.
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.
The speed-time graph of an ascending passenger lift is given alongside. What is the acceleration of the lift:
(1) during the first two seconds ?
(2) between second and tenth second ?
(3) during the last two seconds ?
The graph of one quantity versus another result in a straight line. How are the quantities related to each other?
Interpret the following graph:
What can you say about the nature of motion of a body of its displacement-time graph is:
A straight line parallel to line axis?
Figure shows the distance-time graph of three students A, B and C. On the basis of the graph, answer the following :
When B meets A, where is C?
Figure shows the distance-time graph of three students A, B and C. On the basis of the graph, answer the following :
How far did B travel between the time he passed C and A?
The slope of the speed–time graph gives ______.
