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Question
The reaction between \[\ce{H2(g)}\] and \[\ce{O2(g)}\] is highly feasible yet allowing the gases to stand at room temperature in the same vessel does not lead to the formation of water. Explain.
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Solution
\[\ce{2H2(g) + O2(g) -> 2H2O(I)}\]
This reaction does not take place at room because the activation energy of the reaction is very high.
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