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The pth term of an A.P. is a and qth term is b. Prove that the sum of its (p + q) terms is p+q2[a+b+a-bp-q].

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Question

The pth term of an A.P. is a and qth term is b. Prove that the sum of its (p + q) terms is `(p + q)/2[a + b + (a - b)/(p - q)]`.

Sum
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Solution

Let A be the first term and D be the common difference of the A.P.

It is given that tp = a

⇒ A + (p – 1) D = a  .....(1)

tq = b

⇒ A + (q – 1) D = b  .....(2)

Subtracting (2) from (1), we get

(p – 1 – q + 1) D = a – b

⇒ D = `(a - b)/(p - q)`  .....(3)

Adding (1) and (2), we get

2A + (p + q – 2) D = a + b

⇒ 2A + (p + q – 1) D = a + b + D

⇒ 2A + (p + q – 1) D = `a + b"+ (a - b)/(p - q)`  ....(4)

Now Sp+q = `(p + q)/2 [2"A" + (p + q - 1) "D"]`

= `(p + q)/2[a + b + (a - b)/(p - q)]`  ...[(Using  ...(3) and (4)]

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Chapter 9: Sequences and Series - Solved Examples [Page 150]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 9 Sequences and Series
Solved Examples | Q 2 | Page 150

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