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The First Term of an A.P. is 5, the Common Difference is 3 and the Last Term is 80; Find the Number of Terms.

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Question

The first term of an A.P. is 5, the common difference is 3 and the last term is 80; find the number of terms.

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Solution

Here, a = 5, d = 3, an = 80
Let the number of terms be n.
Then, we have:

\[a_n = a + \left( n - 1 \right)d\]

\[ \Rightarrow 80 = 5 + \left( n - 1 \right)3\]

\[ \Rightarrow 75 = \left( n - 1 \right)3\]

\[ \Rightarrow 25 = \left( n - 1 \right)\]

\[ \Rightarrow 26 = n\]

Thus, there are 26 terms in the given A.P.

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