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Question
The pitch of a screw gauge is 0.5 mm and the head scale is divided in 100 parts. What is the least count of a screw gauge?
Sum
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Solution
Pitch of a screw gauge = 0.5 mm
No. of divisions on the circular scale = 100
L.C. = `(0.5/100)` mm
= 0.005 mm or 0.0005 cm
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Vernier Callipers
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