Advertisements
Advertisements
Question
The following figure shows the reading of a vernier caliper used for measuring the thickness of a metal sheet.
(i) Find the least count of the instrument.
(ii) Calculate the thickness of the metal sheet.
Advertisements
Solution
(i) 1 MSD = 1 mm
10 VSD = 9 mm
1 VSD = `9/10` mm
Least count = 1 MSD - 1 VSD
=`1/10` MSD
= `1/10xx1`mm = 0.1 mm = 0.01 cm
(ii) Thickness of the metal sheet
Main scale reading = 3.9 cm
Vernier scale division coinciding with main scale = 8
Vernier scale reading = 8 x 0.01 cm = 0.08 cm
Thickness of the metal sheet = 3.9 + 0.08 = 3.98 cm
APPEARS IN
RELATED QUESTIONS
Describe in steps, how would you use a vernier callipers to measure the length of a small rod?
Define metre according to the old definition.
Figure shows the position of vernier scale while measuring the external length of a wooden cylinder.
- What is the length recorded by the main scale?
- Which reading of vernier scale coincides with the main scale?
- Calculate the length.
State the formula for determining a pitch
A micrometre screw gauge has a negative zero error of 8 divisions. While measuring the diameter of a wire the reading on the main scale is 3 divisions and the 24th circular scale division coincides with baseline.
If the number of divisions on the main scale are 20 to a centimetre and circular scale has 50 divisions, calculate
- pitch
- observed diameter.
- least count
- corrected diameter.
A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate
- pitch
- observed diameter
- least count
- corrected diameter.
Name the measuring employed to measure the diameter of a pencil.
What is the least count in the case of the following instrument?
Spring balance
