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प्रश्न
The following figure shows the reading of a vernier caliper used for measuring the thickness of a metal sheet.
(i) Find the least count of the instrument.
(ii) Calculate the thickness of the metal sheet.
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उत्तर
(i) 1 MSD = 1 mm
10 VSD = 9 mm
1 VSD = `9/10` mm
Least count = 1 MSD - 1 VSD
=`1/10` MSD
= `1/10xx1`mm = 0.1 mm = 0.01 cm
(ii) Thickness of the metal sheet
Main scale reading = 3.9 cm
Vernier scale division coinciding with main scale = 8
Vernier scale reading = 8 x 0.01 cm = 0.08 cm
Thickness of the metal sheet = 3.9 + 0.08 = 3.98 cm
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संबंधित प्रश्न
Define the term 'Vernier constant'.
Figure shows the position of vernier scale while measuring the external length of a wooden cylinder.
- What is the length recorded by the main scale?
- Which reading of vernier scale coincides with the main scale?
- Calculate the length.
A micrometre screw gauge having a positive zero error of 5 divisions is used to measure diameter of a wire, when reading on the main scale is 3rd division and the 48th circular scale division coincides with baseline. If the micrometer has 10 divisions to a centimetre on the main scale and 100 divisions on a circular scale, calculate
- Pitch of screw
- Least count of screw
- Observed diameter
- Corrected diameter.
For what range of measurement is micrometre screw gauge used?
What do you understand by the following term as applied to micrometre screw gauge?
Baseline
State the formula for calculating the least count of screw.
What is the least count in the case of the following instrument?
Metre scale
