मराठी

State the Purpose of Ratchet in a Screw Gauge. - Physics

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प्रश्न

State the purpose of ratchet in a screw gauge.

टीपा लिहा
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उत्तर

Ratchet helps to advance the screw by turning it until the object is gently held between the stud and spindle of the screw.

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Vernier Callipers
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पाठ 1: Measurements and Experimentation - Exercise 1 (B) [पृष्ठ २०]

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सेलिना Concise Physics [English] Class 9 ICSE
पाठ 1 Measurements and Experimentation
Exercise 1 (B) | Q 18 | पृष्ठ २०

संबंधित प्रश्‍न

A screw gauge has a least count 0.001 cm and zero error +0.007 cm. Draw a neat diagram to represent it.


Describe the procedure to measure the diameter of a wire with the help of a screw gauge.


In the vernier callipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided into 10 parts. While measuring the length, the zero of the vernier lies just ahead of the 1.8 cm mark and the 4th division of vernier coincides with a main scale division.

(a) Find the length.

(b) If zero error of vernier callipers is -0.02 cm,

What is the correct length ?


The pitch of a screw gauge is 1 mm and the circular scale has 100 divisions. In measurement of the diameter of a wire, the main scale reads 2 mm and 45th mark on the circular scale coincides with the base line. Find

(i) The least count and

(ii) The diameter of the wire.


In a vernier callipers, 19 main scale divisions coincide with 20 vernier scale divisions. If the main scale has 20 divisions in a centimetre, calculate

  1. pitch
  2. L.C. of vernier callipers.

State the correction if the negative error is 7 divisions when the least count is 0.01 cm.


The circular scale of a screw gauge has 50 divisions. Its spindle moves by 2 mm on the sleeve, when given four complete rotations calculate

  1. pitch
  2. least count

A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate

  1. pitch
  2. observed diameter
  3. least count
  4. corrected diameter.

What is the backlash error?


If the 4th division of the circular scale coincides with the zero of the main scale of a screw gauge of least count 0.01 mm, what is it's zero error?

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