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प्रश्न
In a vernier callipers, 19 main scale divisions coincide with 20 vernier scale divisions. If the main scale has 20 divisions in a centimetre, calculate
- pitch
- L.C. of vernier callipers.
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उत्तर
Main scale divisions of vernier callipers in one centimetre = 20 Unit
Pitch = `"Unit of main scale"/"Number of divisions in the unit"`
= `1/20` cm
= 0.05 cm
Least count = `"Pitch"/"No. of vernier scale divisions"`
= `0.05/20`
= 0.0025 cm
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संबंधित प्रश्न
Name the part of the vernier callipers which is used to measure the following
Internal diameter of a mug
Explain the terms : Pitch .
How are they determined?
In the vernier callipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided into 10 parts. While measuring the length, the zero of the vernier lies just ahead of the 1.8 cm mark and the 4th division of vernier coincides with a main scale division.
(a) Find the length.
(b) If zero error of vernier callipers is -0.02 cm,
What is the correct length ?
When does a vernier callipers has the negative error?
A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate
- pitch
- observed diameter
- least count
- corrected diameter.
State whether the following statement is true or false by writing T/F against it.
The ratchet of a screw gauge is used to measure the depth of a beaker.
How will you measure the least count of vernier caliper?
