Advertisements
Advertisements
प्रश्न
In a vernier callipers, 19 main scale divisions coincide with 20 vernier scale divisions. If the main scale has 20 divisions in a centimetre, calculate
- pitch
- L.C. of vernier callipers.
Advertisements
उत्तर
Main scale divisions of vernier callipers in one centimetre = 20 Unit
Pitch = `"Unit of main scale"/"Number of divisions in the unit"`
= `1/20` cm
= 0.05 cm
Least count = `"Pitch"/"No. of vernier scale divisions"`
= `0.05/20`
= 0.0025 cm
APPEARS IN
संबंधित प्रश्न
What do you mean by zero error of a screw gauge? How is it accounted for?
Which of the following measures a small length to high accuracy : metre rule , vernier callipers or screw gauge?
While measuring the length of a rod with a vernier callipers, below shows the position of its scales. What is the length of the rod?

When a screw gauge with a least count of 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions.
(i) What is the diameter of the wire in cm?
(ii) If the zero error is +0.005 cm, what is the correct diameter?
A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find
(i) The pitch,
(ii) The least count and
(iii) The zero error of the screw gauge
In figure for vernier callipers, calculate the length recorded.

Least count of a vernier caliper is ______ cm.
