Advertisements
Advertisements
प्रश्न
How do you account for positive zero error for calculating the correct diameter of wires?
Advertisements
उत्तर
If the zero lines, marked on a circular scale, is below the reference line of the main scale, then there is a positive zero error and the correction is negative. In figure 5th, circular scale division is coinciding with the reference line.
∴ Correction = – Coinciding division of C.S. × L.C.
= – 5 × 0.001 cm
= – 0.005 cm
If the observed diameter is 0.557 cm, then:
Corrected diameter
= Observed diameter + Correction
= 0.557 cm – 0.005 cm
= 0.552 cm
APPEARS IN
संबंधित प्रश्न
Define the least count of vernier callipers. How do you determine it?
Draw a neat and labelled diagram of a vernier callipers. Name its main parts and state their functions.
A pendulum completes 2 oscillations in 5 s. What is its time period? If g = 9.8 m s-2, find its length.
Who invented vernier callipers?
The circular scale of a screw gauge has 100 divisions. Its spindle moves forward by 2.5 mm when given five complete turns. Calculate
- pitch
- least count of the screw gauge
A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate
- pitch
- observed diameter
- least count
- corrected diameter.
What do you understand by the following term as applied to screw gauge?
Zero error
State whether the following statement is true or false by writing T/F against it.
The metre scale, vernier calipers, and screw gauge are in decreasing order of least count.
The precision of vernier calipers is ______ mm.
