Advertisements
Advertisements
प्रश्न
How do you account for positive zero error for calculating the correct diameter of wires?
Advertisements
उत्तर
If the zero lines, marked on a circular scale, is below the reference line of the main scale, then there is a positive zero error and the correction is negative. In figure 5th, circular scale division is coinciding with the reference line.
∴ Correction = – Coinciding division of C.S. × L.C.
= – 5 × 0.001 cm
= – 0.005 cm
If the observed diameter is 0.557 cm, then:
Corrected diameter
= Observed diameter + Correction
= 0.557 cm – 0.005 cm
= 0.552 cm

APPEARS IN
संबंधित प्रश्न
The wavelength of light is 589 nm. what is its wavelength in Å?
A vernier callipers has a zero error of + 0.06 cm. Draw a neat labelled diagram to represent it.
A screw gauge has a least count 0.001 cm and zero error +0.007 cm. Draw a neat diagram to represent it.
A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of the circular scale lies below the base line and 4th division of the circular scale is in line with the base line. Find
(i) The pitch,
(ii) The least count and
(iii) The zero error of the screw gauge
Figure shows a screw gauge in which circular scale has 200 divisions. Calculate the least count and radius of the wire.

A micrometre screw gauge has a positive zero error of 7 divisions, such that its main scale is marked in 1/2 mm and the circular scale has 100 divisions. The spindle of the screw advances by 1 division complete rotation.
If this screw gauge reading is 9 divisions on the main scale and 67 divisions on the circular scale for the diameter of a thin wire, calculate
- Pitch
- L.C.
- Observed diameter
- Corrected diameter
How do you account for negative zero error, for calculating the correct diameter of wires?
Thickness of a cricket ball is measured by ______.
