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प्रश्न
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
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उत्तर
No. of circular scale division = 100
Pitch =0.5 mm
= `(0.5 "mm")/100`
= 0.005 mm
L.C. = 0.005 mm = 0.0005 cm
Main scale reading = 4.5 mm = 0.45 cm
(C.S.D.) circular scale reading = 73 division
Observed diameter of wire = Main scale reading + L.C. × C.S.D.
= 0.45 + 0.0005 × 73
= 0.45 + 0.0365
= 0.4865 cm
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संबंधित प्रश्न
Draw a neat and labelled diagram of a vernier callipers. Name its main parts and state their functions.
State the purpose of ratchet in a screw gauge.
The pitch of a screw gauge is 0.5 mm and the head scale is divided in 100 parts. What is the least count of a screw gauge?
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Which part of vernier callipers is used to measure the external diameter of a cylinder?
What is the least count in the case of the following instrument?
Thermometer
The following diagrams (Fig. 5) show the use of a vernier caliper under three different situations. Study the diagrams carefully and note down the vernier readings in each case.
(a) Measuring the diameter of the rod
(b) Measuring Internal diameter of a cavity
(c) Measuring depth of a cavity
The precision of vernier calipers is ______ mm.
