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प्रश्न
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
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उत्तर
No. of circular scale division = 100
Pitch =0.5 mm
= `(0.5 "mm")/100`
= 0.005 mm
L.C. = 0.005 mm = 0.0005 cm
Main scale reading = 4.5 mm = 0.45 cm
(C.S.D.) circular scale reading = 73 division
Observed diameter of wire = Main scale reading + L.C. × C.S.D.
= 0.45 + 0.0005 × 73
= 0.45 + 0.0365
= 0.4865 cm
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संबंधित प्रश्न
The pitch of a screw gauge is 1 mm and the circular scale has 100 divisions. In measurement of the diameter of a wire, the main scale reads 2 mm and 45th mark on the circular scale coincides with the base line. Find
(i) The least count and
(ii) The diameter of the wire.
Define metre according to the old definition.
The final result of the calculation in an experiment is 125,347,200. Express the number in term of significant place when accuracy is between 1 and 10
State the formula for calculating the pitch of screw.
What do you understand by the following term as applied to screw gauge?
Positive zero error
What do you understand by the following term as applied to screw gauge?
Negative zero error
