Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
In this case, the zero error is negative
Least count of screw gauge = 0.01 mm
Thus, zero error = (50-47) X L.C.
= 3 X 0.01
= 0.03 mm
APPEARS IN
संबंधित प्रश्न
Define the least count of vernier callipers. How do you determine it?
Name the part of the vernier callipers which is used to measure the following
Depth of a small bottle
Name the part of the vernier callipers which is used to measure the following
Thickness of a pencil.
A pendulum completes 2 oscillations in 5 s. What is its time period? If g = 9.8 m s-2, find its length.
The least count of a vernier callipers is 0.01 cm and it has an error of + 0.07 cm. While measuring the radius of a sphere, the main scale reading is 2.90 cm and the 5th vernier scale division coincides with the main scale. Calculate the correct radius.
State whether the following statement is true or false by writing T/F against it.
The metre scale, vernier calipers, and screw gauge are in decreasing order of least count.
What is meant by the pitch of a screw gauge? The pitch of a screw is 1 mm.
Find the reading of the instrument shown in the following figure.

How will you find the Zero Error of Vernier Caliper? Explain.
